Question

Evaluate quantity the square root of 36 times 3 squared minus the cube root of negative 64 end quantity divided by 2 squared.

Answer 1

Answer: 58/4

Step-by-step explanation:

Answer 2

$\cfrac{\sqrt{36}\cdot 3^2-\sqrt[3]{-64}}{2^2}\implies \cfrac{\sqrt{6^2}\cdot 3^2-\sqrt[3]{(-4)^3}}{2^2}\implies \cfrac{6\cdot 3^2-(-4)}{2^2} \\\\\\ \cfrac{6\cdot 9-(-4)}{4}\implies \cfrac{54-(-4)}{4}\implies \cfrac{54+4}{4}\implies \cfrac{58}{4}$

notice, PEMDAS

groups first, then Exponents, then Multiplication and Division from left-to-right, then Addition and Subtraction from left-to-right last.