Answer:
12.8
Step-by-step explanation:
Given a parabola in standard form , ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= - 
h = 3 + 14t - 5t² ← is in standard form
with a = - 5 and b = 14, thus
= - 
= 1.4
Substitute t = 1.4 into h for maximum height
h = 3 + 14(1.4) - 5(1.4)²
= 3 + 19.6 - 9.8 = 12.8
Figure 2 and 4. The translation method was used . Figure 2 was moved to the right and enlarged. They’ve still maintained the same shape however only enalarged.
Figure 4 has only decreased in size.
Please mark as a brainliest will be much appreciated
the answer is the last one: a 90° clockwise rotation
Assuming metric units, metre, kilogram and seconds
Best approach: draw a free body diagram and identify forces acting on the child, which are:
gravity, which can be decomposed into normal and parallel (to slide) components
N=mg(cos(theta)) [pressing on slide surface]
F=mg(sin(theta)) [pushing child downwards, also cause for acceleration]
m=mass of child (in kg)
g=acceleration due to gravity = 9.81 m/s^2
theta=angle with horizontal = 42 degrees
Similarly, kinetic friction is slowing down the child, pushing against F, and equal to
Fr=mu*N=mu*mg(cos(theta))
mu=coefficient of kinetic friction = 0.2
The net force pushing child downwards along slide is therefore
Fnet=F-Fr
=mg(sin(theta))-mu*mg(cos(theta))
=mg(sin(theta)-mu*cos(theta)) [ assuming sin(theta)> mu*cos(theta) ]
From Newton's second law,
F=ma, or
a=F/m
=mg(sin(theta)-mu*cos(theta)) / m
= g(sin(theta)-mu*cos(theta)) [ m/s^2]
In case imperial units are used, g is approximately 32.2 feet/s^2.
and the answer will be in the same units [ft/s^2] since sin, cos and mu are pure numbers.
