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kozerog [31]
3 years ago
13

Plz, answer! 34 + 2 ⋅ 5 =

Mathematics
2 answers:
8_murik_8 [283]3 years ago
6 0

3^{4} + 2 × 5

To evaluate apply the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

Parentheses  

There are none for this steps so go on to the next step

Exponent:

3^{4}

81

so...

81 + 2 × 5

Multiplication:

81 + 2 × 5

2 × 5

10

so...

81 + 10

No division in this equation so skip this step and go to the next one

Addition:

81 + 10

91

Hope this helped!

~Just a girl in love with Shawn Mendes

UkoKoshka [18]3 years ago
4 0

<em>Answer:</em>

<em>44</em>

<em>Step-by-step explanation:</em>

<em>Order of operations</em>

<em>PEMDAS</em>

<em>Parenthesis</em>

<em>Exponent</em>

<em>Multiply</em>

<em>Divide</em>

<em>Add</em>

<em>Subtract</em>

<em>Do multiply from left to right.</em>

<em>2*5=10</em>

<em>Add the numbers from left to right to find the answer.</em>

<em>34+10=44</em>

<em>44 is the correct answer.</em>

<em>I hope this helps you, and have a wonderful day!</em>

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What product is shown by the model 50 and 35
VikaD [51]
What product is shown by the model 50 and 35?

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6 0
3 years ago
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1. Find 3 consecutive integers whose sum is 33.
statuscvo [17]

Answer: 10, 11, 12

Step-by-step explanation: Think of the integers like this:

1st integer: x

2nd integer: x+1

3rd integer: x+2

That is necessary because they are consecutive integers. Since the sum is 33, we need to create an equation.

x+x+1+x+2=33.

Simplify:

3x+3=33.

Opposite operations:

3x=-3+33.

To get the 3 close to the 33, we needed to make it negative, which is the opposite operation of the positive 3.

So,

3x=30.

Divide by 3:

x=10.

The first integer, x, equals 10.

To go with the guide that we already created,

1st integer: x=10

2nd integer: x+1=11

3rd integer:x+2=12.

Therefore, the three consecutive integers are 10, 11, and 12.

To check that, add them up. They all equal 33 and they are consecutive, which means this is the right answer!

5 0
3 years ago
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Answer:

See Below

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Amiraneli [1.4K]
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