Question

PLEASE HELP!!

Answer 1

$f(x) = 2 {}^{x} \\ g(x) = f(x + 2) = 2 {}^{x + 2} \\ g(x) = 2 {}^{x + 2} =2 {}^{x} .2 {}^{2} = 4.2 {}^{x}$

$a.b {}^{x} = > horizontal \: asymp \: y = 0$

$4.2 {}^{0} = 4 = > vertical \: int \: (0,4)$

$a.b {}^{x} = > x ∈ \: ] -∞ , ∞ [$

Answer: Options:

2 4 5

Answer 2

The horizontal asymptote of the function f ( x ) = 2ˣ is y = 0 and the y-intercept is ( 0 , 4 )

What are Asymptotes?

An asymptote is a line that a curve approaches but never touches. A line where the graph of a function converges is known as an asymptote. When graphing functions, asymptotes are typically not required

There are 3 types of asymptotes

Horizontal asymptote (HA) - It is a horizontal line and hence its equation is of the form y = k. Horizontal Asymptote is when the function f(x) is tending to zero

Vertical asymptote (VA) - It is a vertical line and hence its equation is of the form x = k. Vertical asymptotes are defined when the denominator of a rational function tends to zero

Slanting asymptote (Oblique asymptote) - It is a slanting line and hence its equation is of the form y = mx + b

Given data ,

Let the function be denoted as f ( x )

Now , the value of f ( x ) is

f ( x ) = 2ˣ   be equation (1)

The y-intercept of the function is when x = 0

So , when x = 0

f ( 0 ) = 2⁰

f ( 0 ) = 1

So , the y-intercept of the function is at ( 0 , 4 )

And , when the function f ( x ) is tending to zero , the horizontal asymptote is y = 0

Therefore , the horizontal asymptote is y = 0

The domain of the exponential function is { -∞ < x < ∞ }

Hence , the horizontal asymptote of the function f ( x ) = 2ˣ is y = 0

To learn more about asymptotes click :

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