It would be exactly $3.00
The matrix equation that can be solved to find all the respective costs is;
![\left[\begin{array}{ccc}2&3&50\\4&6&100\\2&5&80\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}51\\90\\78\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%2650%5C%5C4%266%26100%5C%5C2%265%2680%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D51%5C%5C90%5C%5C78%5Cend%7Barray%7D%5Cright%5D)
<h3>How to create matrix equations?</h3>
Let cost of admission for children be x.
Let cost of admission for adults be y.
Let cost of admission for carnival tickets be z.
Thus, we have the simultaneous equation as;
2x + 3y + 50z = 51
4x + 6y + 100z = 90
2x + 5y + 80z = 78
Thus, writing this in matrix form gives;
![\left[\begin{array}{ccc}2&3&50\\4&6&100\\2&5&80\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}51\\90\\78\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%2650%5C%5C4%266%26100%5C%5C2%265%2680%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D51%5C%5C90%5C%5C78%5Cend%7Barray%7D%5Cright%5D)
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Answer:
Triangles A and E could lie on a graphed lin with a slope of 6
Triangles B and F could lie ona graphed line with a slope of 1/4
Triangles C and D could lie on a graphed line with a slope of 2/5
Step-by-step explanation:
The slope is rise over run.
Triangle A goes up 54 and to the right 9 so the slope is 54/9=6
Triangle B goes up 15 and to the right 60 so the slope is 15/60=1/4
Triangle C goes up 18 and to the right 45 so the slope is 18/45=2/5
Triangle D goes up 16 and to the right 40 so the slope is 16/40=2/5
Triangle E goes up 72 and to the right 12 so the slope is 72/12=6
Triangle F goes up 13 and to the right 52, so the slope is 13/52=1/4
From there we can find which slopes are the same.
Answer:
Hai
Step-by-step explanation:
A=πr^2, that is for the total area of the circle. However we only want the area of the sector enclosed by 172° so
A=172πr^2/360, since r=12
A=172π*144/360
A=68.8π u^2
A≈216.14 u^2 (to nearest hundredth of a unit)