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2 years ago

10

Un terreno rectangular cuyo ancho mide 20 mts menos que su largo. Su área del terreno es de 150 metros cuadrados. ¿Determina las

medidas del largo y del ancho?

1 answer:

IrinaVladis [17]2 years ago

7 0

Answer:

you are a good friend Sayed im not sure if I can get it done before I get my license back and the whole time we go back and be out in a bit I guess that was the best thing I ever heard of the beast's I have

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I need help with this

Harlamova29_29 [7]

Answer:

50 degrees.

Step-by-step explanation:

The three angles make up a straight line angle which = 180 degrees, so:

C = 180 - 65 - 65

= 50 degrees.

7 0

2 years ago

Read 2 more answers

Pls only do this if yk it because i’m giving correct answer brainliest! :))

Leno4ka [110]

Answer:

$x=2+\frac{1}{2}\sqrt[]{21}$

or

$x=2-\frac{1}{2}\sqrt{{21}$

Step-by-step explanation:

$4x^2-16x-26=-21$

Add 21 on both sides.

$4x^2-16x-26+21=-21+21$

$4x^2-16x-5=0$

a=4

b=-16

c=-5

$x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}$

$x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)} }{2(4)}$

$x=\frac{16\frac{+}{}\sqrt[]{256+80} }{8}$

$x=\frac{16\frac{+}{}\sqrt[]{336} }{8}$

$x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21} }{8}$

$x=\frac{16\frac{+}{}2*2\sqrt[]{21} }{8}$

$x=\frac{16\frac{+}{}4\sqrt[]{21} }{8}$

---------------------------------------------------------------------------

$x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}$

$x=2+\frac{1}{2}\sqrt[]{21}$

---------------------------------------------------------------------------

$x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}$

6 0

3 years ago

Read 2 more answers

Solve for m. –8m = 3 − 9m m =

Oksanka [162]

Answer:

m=3

Step-by-step explanation:

–8m = 3 − 9m

-8+9m = 3

m = 3

8 0

3 years ago

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Help please math thank you

bija089 [108]

Answer:

5

Step-by-step explanation:

4 0

2 years ago

Factor 10c^2-60cd +80d^2

ozzi

$10c^2-60cd +80d^2$

$(2c - 8d) (5c -10d)$

$this \\ is \\ because...$

$2c*5c=10c^2$

$2c * -10d=-20cd \\ -8d*5c=-40cd \\ -20cd-40cd=-60cd$

$-8d * -10d = 80d$

5 0

3 years ago