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Zinaida [17]
2 years ago
5

Which compound contains a chiral carbon atom? 3-chloropentane 2-bromopropane 3-bromopentane 2-bromopentane

Chemistry
1 answer:
kozerog [31]2 years ago
8 0

The compound  2-bromopentane contains a chiral carbon atom.

So , option D is correct one.

The carbon which is bonded with four different substituent or four valency of carbon is satisfy by the four different substituent is called chiral carbon and the molecule contain such chiral carbon is called chiral molecule. The molecule contain chiral carbon rotates plane polarized light.

Example: The compound  2-bromopentane contains chiral carbon at second carbon and four different substituent at second carbon is methyl , bromine , propyl and hydrogen.

learn more about chiral carbon

brainly.com/question/28167696

#SPJ4

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You are asked to prepare 500 mL 0.200 M acetate buffer at pH 5.00 using only pure acetic acid ( MW=60.05 g/mol, pKa=4.76), 3.00
Vilka [71]

Answer:

You need to weight 6,005 g of acetic acid

Explanation:

Using Henderson-Hasselbalch formula you will obtain:

5,00 = 4,76 +log₁₀ \frac{[Ac^-]}{[Acac]}

<em>Where Ac⁻ is the salt of acetic acid (Acac).</em>

Solving:

1,738 = \frac{[Ac^-]}{[Acac]} <em>(1)</em>

Also, yo know that:

0,200 M = [Ac⁻] + [Acac] <em>(2)</em>

Replacing (2) in (1):

[Acac] = 0,0730 M.

Thus:

[Ac⁻] = 0,127 M

The moles of each compound are:

Acac = 0,0730 M × 0,500 L = <em>0,0365 mol</em>

Ac⁻ = 0,127 M × 0,500 L = <em>0,0635 mol</em>

To prepare these moles it is necessary to use:

Acac + NaOH → AcNa + H₂O

The initial moles of Acac must be:

0,0365 moles + 0,0635 moles = 0,100 moles

<em>To obtain 0,0635 moles of Ac⁻ you need to take this quantity of NaOH moles.</em>

Thus, to obtain a acetate buffer of 5,00 you need to add 0,100 moles of acetic acid and 0,0635 moles of NaOH because This NaOH will react with acetic acid producing 0,0635 moles of Ac⁻ and surplus 0,0365 moles of acetic acid.

Now, to obtain 0,100 moles of acetic acid from pure acetic acid:

0,100 moles × \frac{60,05 g}{1 mol} = <em>6,005 g</em>

<em>You need to weight 6,005 g of acetic acid</em>

I hope it helps!

7 0
4 years ago
Please help me answer these 3 questions
aleksandr82 [10.1K]

Explanation:

Photosynthesis is the process by which green plants manufacture their food using carbon dioxide and water in the presence of sunlight.

It is expressed using the equation below;

      6CO₂   +   6H₂O     →      C₆H₁₂O₆  +  6O₂

         reactants                      products

1. Compounds consumed are carbon dioxide and water.

2. Product is glucose and oxygen.

3. Most organism obtain their nourishment directly and indirectly from photosynthetic activities.

Plants are the producers of food in the ecosystem. If the process of photosynthesis does not occur, there is no way other organisms will obtain their own nourishment.

3 0
3 years ago
While a match burns what type of change occurs?
kotegsom [21]
Physicalchange. Lighting a match and letting is burn is an example of a chemical change. Chemical reactions cause chemicalchanges. In a chemical reactiontwo or more substances, called the reactants, form different substances called products.
8 0
3 years ago
. Which type of rock would be affected the most by the<br> water cycle?
likoan [24]

Answer:

maybe talc because it is the softest type of rock

Explanation:

5 0
3 years ago
6 Fe2+ (aq) + Cr2O72− (aq) + 14 H+ (aq) → 6 Fe3+ (aq) + 2 Cr3+ (aq) + 7 H2O (aq) If the titration of 23 mL of an iron(II) soluti
ratelena [41]

Answer:

1.047 M

Explanation:

The given reaction:

6Fe^{2+}_{(aq)}+Cr_2O_7^{2-}_{(aq)}+14H^+_{(aq)}\rightarrow 6Fe^{3+}_{(aq)}+2Cr^{3+}_{(aq)}+7H_2O_{(aq)}

For dichromate :

Molarity = 0.254 M

Volume = 15.8 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.8 ×10⁻³ L

Thus, moles of dichromate :

Moles=0.254 \times {15.8\times 10^{-3}}\ moles

Moles of dichromate = 0.0040132 moles

1 mole of dichromate react with 6 moles of iron(II) solution

Thus,

0.0040132 moles of dichromate react with 6 × 0.0040132 moles of iron(II) solution

Moles of iron(II) solution = 0.02408 moles

Volume = 23 mL = 0.023 L

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

<u>Molarity = 0.02408 / 0.023 = 1.047 M</u>

7 0
3 years ago
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