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Dmitry [639]
3 years ago
14

Which intermolecular forces do the particles in the image (F– in water) experience? Note that the ion is not necessarily drawn t

o scale.

Chemistry
1 answer:
Lena [83]3 years ago
3 0

hydrogen bonding and ion-dipole

Explanation:

The intermolecular forces the particles of fluoride experiences is an ion-dipole bond, between the water molecules, there are hydrogen bonds.

  • An ion-dipole bond is an attractive force between an ion and a polar molecule.
  • The fluoride is the anion that is attracted by the positive end of water molecules.
  • Water is a polar compound.
  • Between the water molecule, there is presence of hydrogen bonds.
  • Hydrogen bonds are special dipole - dipole attraction between polar molecules joined to a highly electronegative atom.
  • The electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule forms the hydrogen bond.

learn more:

Hydrogen bond brainly.com/question/10602513

#learnwithBrainly

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I need help with this question
Maru [420]

Aluminum sulfide : Al₂S₃

ratio cation : anion = 2 : 3

<h3>Further explanation</h3>

Given

Compound of Aluminium

Required

cations anions ratio

Solution

Salt can be formed from cations and anions which have their respective charges.

In the chemical compound formula these charges are crossed with each other

For aluminum it has a +3 charge

1. Aluminum carbide : Al₄C₃

ratio cation : anion = 4 : 3

2. Aluminum chloride : AlCl₃

ratio cation : anion = 1 : 3

3. Aluminum sulfide : Al₂S₃

ratio cation : anion = 2 : 3

4. Aluminum nitride : AlN

ratio cation : anion = 1 : 1

3 0
3 years ago
Which example best describes a double displacement reaction?
Inessa05 [86]

Answer:

The first one would describe it best

Explanation:

The second option sounds like a single displacement reaction

The third is a decomposition reaction

ANd the first is a combination reaction

6 0
4 years ago
Read 2 more answers
In a certain city, electricity costs $ 0.18 per kW ⋅ h . What is the annual cost for electricity to power a lamppost for 5.00 h
LuckyWell [14K]

Answer:

The cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

Explanation:

Cost of electricity = $ 0.18 per KW-H

Time = 5 hour per day

Bulb power = 100 W = 0.1 KW

Fluorescent bulb power = 25 W = 0.025 KW

(a) Cost of electricity for 100 W power bulb

0.1 × 5 × 365 × 0.18 =  $ 32.85

(b) Cost of electricity for 0.025 W  fluorescent  bulb

0.025 × 5 × 365 × 0.18 = $ 8.2125

Therefore the cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

6 0
4 years ago
Write the formulas for the following compounds: (a) copper(l) cyanide, (b) strontium chlorite, (c) perbromic acid,(d) hydroiodic
Romashka [77]

Answer:

A. CuCN

B. Sr(OCl)2

C. HBrO4

D. HI

E. Na2NH4PO4

F. KH2PO4

G. IF7

H. P4S10

I. HgO

J. Hg2I2

K. SeF6

Explanation:

All have different valent cation and anions like mono di and poly valent ions

4 0
4 years ago
A chemist prepares a solution of potassium iodide (KI) by measuring out 88. umol of potassium iodide into a 200. mL volumetric f
max2010maxim [7]

The concentration in mol/L of the chemist's potassium iodide solution : = 4.4 x 10⁻⁴ M

<h3>Further explanation</h3>

Given

88. μmol of Potassium iodide

200. mL volumetric flask

Required

The concentration

Solution

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Conversion :

88. μmol = 88 . 10⁺⁶ mol = 8.8 10⁻⁵ mol

200 ml = 0.2 L

The molarity :

= n : V

= 8.8.10⁻⁵ : 0.2

= 4.4 x 10⁻⁴ M

4 0
3 years ago
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