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kykrilka [37]
3 years ago
13

8) When two atoms form a chemical bond_________.

Chemistry
1 answer:
Alexxandr [17]3 years ago
4 0

Answer:

The electrons of an atom that can participate in the formation of chemical bonds with other atoms.

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3 years ago
Oceanography does not include the study of which of the following topics?
MrRissso [65]

Answer:

A. The relationship between the Sun,Moon,and Earth

Explanation:

5 0
3 years ago
If 3.85 mL of 10.0 M NaOH is used for a reaction, calculate the number of moles of NaOH that were used.
Lena [83]

The number of mole of NaOH that was used, given that 3.85 mL of 10.0 M NaOH is used in the reaction is 0.0385 mole

<h3>How do I determine the number of mole of NaOH?</h3>

We know that molarity is related to number of mole and volume according to the following formula:

Molarity = number of mole / Volume

With the above formula, we can determine the number of mole of NaOH. Details below

The following data were obtained from the question:

  • Volume = 3.85 mL = 3.85 / 1000 = 0.00385 L
  • Molarity = 10.0 M
  • Number of mole of NaOH =?

Molarity = number of mole / Volume

Cross multiply

Number of mole = molarity × volume

Number of mole of NaOH = 10 × 0.00385

Number of mole of NaOH = 0.0385 mole

Thus, the number of mole of NaOH is 0.0385 mole

Learn more about number of mole:

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4 0
2 years ago
2. This graph shows the energy involved in a reaction involving two molecules. Describe what is happening or what the state of t
blagie [28]
If you think of it endothermic is when there is energy needed for the reaction to occur and exothermic is when the reaction releases energy
6 0
3 years ago
The Haber process for the production of ammonia is the main industrial process of producing ammonia today. Prior to developing t
Schach [20]

Answer:

Equilibrium constant for the reaction at 25⁰C = 1.81 x 10⁻⁶

Explanation:

                            Reaction for the Haber's process

                              N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g)

Free energy change of reaction

                    ΔGr° = ∑products free energy - ∑reactants free energy

                             = 2 x (- 16.4) - 0

                             = - 32.8 KJ / mole

Equilibrium constant for this reaction at 25⁰C

                           ΔGr° = - 2.303 RT log K

                      ⇒  log K = \frac{-32.8}{2.303 X8.314X10^{-3}X 298 }

                      ⇒        K = Anti log( -5.74) = 1.81 x 10⁻⁶

6 0
4 years ago
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