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Mnenie [13.5K]
3 years ago
12

During strenuous exercise, the NADH formed in the glyceraldehyde 3-phosphate dehydrogenase reaction in skeletal muscle must be r

eoxidized to NAD+ if glycolysis is to continue. The most important reaction involved in the reoxidation of NADH is:
A) dihydroxyacetone phosphate → glycerol 3-phosphate
B) glucose 6-phosphate → fructose 6-phosphate
C) isocitrate → α-ketoglutarate
D) oxaloacetate → malate
E) pyruvate → lactate
Chemistry
1 answer:
vekshin13 years ago
6 0

Answer:

The answer is pyruvate → lactate

Explanation:

In the reaction of glycolysis, glucose breaks down to form pyruvate yielding ATP and NADH.

Under or during strenuous exercise, which is an anaerobic condition, lactate is formed by the reoxidization of NADH and the conversion of pyruvate to lactate.

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A composition of reflections over parallel lines is the same as a __________.
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Answer : Option A) Translation


Explanation : A composition of reflections over parallel lines is the same as a <u>Translation.</u>


To identify if the composition of reflections over parallel lines are same as translation or not?


We can check using a picture of some shape in the plane. Place the picture on the right side of two vertical parallel. Now, we can see the reflected the shape over the nearest parallel line, then check the reflection over the other parallel line. We see that the shape winds up in the same orientation, like it was just shifted over to the right. Hence, it is translation.

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There is about 1.0 g of calcium as Ca2+ in 1.0 L of milk. What is the molarity of Ca2+ in milk?
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Explanation:

It is known that molarity is the number of moles present in a liter of solution.

           Molarity = \frac{\text{no. of moles}}{volume}

Also, number of moles equal mass divided by molar mass. And, molar mass of calcium is 40.07 g/mol.

               No. of moles = \frac{mass}{\text{molar mass}}

                                     = \frac{1.0 g}{40.07 g/mol}

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Therefore, calculate the molarity as follows.

             Molarity = \frac{\text{no. of moles}}{volume}

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