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Mnenie [13.5K]
3 years ago
12

During strenuous exercise, the NADH formed in the glyceraldehyde 3-phosphate dehydrogenase reaction in skeletal muscle must be r

eoxidized to NAD+ if glycolysis is to continue. The most important reaction involved in the reoxidation of NADH is:
A) dihydroxyacetone phosphate → glycerol 3-phosphate
B) glucose 6-phosphate → fructose 6-phosphate
C) isocitrate → α-ketoglutarate
D) oxaloacetate → malate
E) pyruvate → lactate
Chemistry
1 answer:
vekshin13 years ago
6 0

Answer:

The answer is pyruvate → lactate

Explanation:

In the reaction of glycolysis, glucose breaks down to form pyruvate yielding ATP and NADH.

Under or during strenuous exercise, which is an anaerobic condition, lactate is formed by the reoxidization of NADH and the conversion of pyruvate to lactate.

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The following mechanism has been proposed for the conversion of tert-butyl bromide to tert-butyl alcohol in aqueous solution: st
Gelneren [198K]

Answer:

See explanation

Explanation:

The first step in this reaction is a unimolecular reaction. It involves the formation of the carbocation. This is so because tertiary alkyl halides only undergo substitution by SN1 mechanism due to sterric crowding.

The second step in the reaction is bi molecular. In this step, the carbocation now combines with the OH^- to yield the alcohol.

Net equation of the reaction is;

(CH3)3CBr + OH^- -------> (CH3)3COH + Br^-

The intermediate here is the carbocation,  (CH3)3C^+

8 0
3 years ago
For the reaction, 2A + B → 3C, rate of disappearance of A is 0.3 M/s in a certain time interval.What is the average rate of appe
andrezito [222]

Answer:

E) rate of appearance of C = 0.45 M/s

rate of the reaction = 0.15 M/s

Explanation:

2A + B → 3C

Writing rate law for the reaction:

<u>Rate of reaction</u> = -\frac{1}{2}\frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{1}{3}\frac{d[C]}{dt} → equation 1

Given that the rate of disappearance of A is 0.3 M/s

⇒ - \frac{d[A]}{dt} = 0.3 M/s

⇒Rate of reaction = - \frac{1}{2}\frac{d[A]}{dt} = \frac{1}{2}×0.3 M/s

⇒<u>Rate of reaction = 0.15 M/s</u>

From equation 1, \frac{d[C]}{dt} = - \frac{3}{2}\frac{d[A]}{dt} = \frac{3}{2}×0.3 M/s

⇒\frac{d[C]}{dt} = 0.45 M/s

or <u>the rate of appearance of C = 0.45 M/s</u>

7 0
3 years ago
brass paper clips that have a golden color have 33% zinc and 67% copper. paper clips made of brass,which appear more red in colo
Yuki888 [10]

Answer:

Density

Explanation:

7 0
3 years ago
What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to
Ray Of Light [21]

Answer:

≈ 395,8 J/(kg * °C)

Explanation:

m = 44 g = 0,044 kg

t_{1} = 22 °C

t_{2} = 33,6 °C

Q = 202 J

The formula is: Q = c * m * (t_{2} - t_{1})

c = \frac{Q}{m * (t_{2} - t_{1} )}

Calculating:

c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)

4 0
3 years ago
in simple diffusion, molecules move from an area of ____ concentration to an area of ____ concentration.
liq [111]

Answer:

high, low

Explanation:

In simple diffusion, molecules move from an area of high concentration to an area of low concentration.

6 0
2 years ago
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