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Anni [7]
1 year ago
3

Calculate the minimum energy released for each of the given particle-antiparticle annihilations: (a) electron and positron (b) m

uon and anti-muon (c) tau and anti-tau (d) proton and anti-proton
Chemistry
1 answer:
lara31 [8.8K]1 year ago
7 0

(a) The minimum energy released for  electron and positron = 1.02 MeV

(b) The minimum energy released for muon and anti-muon = 106.1 MeV

(c) The minimum energy released for tau and anti-tau = 1775 MeV

(d) The minimum energy released for proton and anti-proton = 1876 MeV

(a) electron and positron

Rest  mass of electron and positron = 9.1×10^{-31}kg.

E = Δmc^{2}

E = 2m_{0} c^{2}

  = 2 × 9.1×10^{-31} × (3×10^{8}) × (3×10^{8})

1 MeV = 1.602×10^{-13} J

So, E = 2 × 9.1×10^{-31} × (3×10^{8}) × (3×10^{8}) / 1.602×10^{-13}

E = 1.02 MeV

The minimum energy released for  electron and positron = 1.02 MeV

(b) muon and anti-muon

Rest  mass of muon and anti-muon = 1.89×10^{28}kg

E = Δmc^{2}

E = 2m_{0} c^{2}

  = 2 × 1.89×10^{-28} × (3×10^{8}) × (3×10^{8})

1 MeV = 1.602×10^{-13} J

So, E = 2 × 1.89×10^{-28} × (3×10^{8}) × (3×10^{8}) / 1.602×10^{-13}

         = 17.01 × 10^{-12}  / 1.602×10^{-13}  = 10.61 × 10

E = 106.1 MeV

The minimum energy released for muon and anti-muon = 106.1 MeV

(c)tau and anti-tau

Rest  mass of tau and anti-tau = 3.16×10^{-27}kg

E = Δmc^{2}

E = 2m_{0} c^{2}

  = 2 × 3.16×10^{-27} × (3×10^{8}) × (3×10^{8})

1 MeV = 1.602×10^{-13} J

So, E = 2 ×3.16×10^{-27} × (3×10^{8}) × (3×10^{8}) / 1.602×10^{-13}

         = 28.44 × 10^{-11}  / 1.602×10^{-13}  = 17.75 × 10^{2}

E = 1775 MeV

The minimum energy released for tau and anti-tau = 1775 MeV

(d)  proton and anti-proton

E = Δmc^{2}

E = 2m_{0} c^{2}

  = 2 × 1.67×10^{-27} × (3×10^{8}) × (3×10^{8})

1 MeV = 1.602×10^{-13} J

So, E = 2 ×1.67×10^{-27} × (3×10^{8}) × (3×10^{8}) / 1.602×10^{-13}

         = 30.06 × 10^{-11}  / 1.602×10^{-13}  = 18.76 × 10^{2}

E = 1876 MeV

The minimum energy released for proton and anti-proton = 1876 MeV

Learn more about  minimum energy here;

brainly.com/question/1489539

#SPJ4

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