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Naddik [55]
3 years ago
11

4. What are the possible genotypes of the pes plant?

Chemistry
1 answer:
shtirl [24]3 years ago
8 0
PPRR, PpRR, PPRr, and PpRr
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Please help me lol
Shtirlitz [24]

Answer:

in 4 liters of solution

MgSO4) are dissolved in 0.965 L of a 0.0575 M solution? Molar Mass Mg: 24.30 g/mol Molar Mass S: 32.06 g/mol Molar Mass O: 16.00 g/

8 0
3 years ago
Shown below is a balance. Based on this instrument, identify from the following list all the statements that are true if you wer
kirill115 [55]

From the image shown, the uncertainty in the weighing balance extends to the hundredth place.

<h3>What is a balance?</h3>

A balance is any device that is used for measuring the mass or weight of an object. The balance is a necessary instrument in every laboratory.

Looking at the image shown, the following are true;

  • the uncertainty is in the hundredth place.
  • a mass that falls between 1 gram and 9 grams measured on this balance will always have 3 significant figures.

Learn more about weighing balance: brainly.com/question/8902159

5 0
2 years ago
What's the answer ???
lesya692 [45]
The answer would be step three but not positive this is correct hope this helps
5 0
3 years ago
What is the mass percent of nitrogen in ammonium carbonate, (NH4)2CO3?
Margaret [11]

In order for you to calculate for the mass of ammonium carbonate, you need to know the molar mass of it and the nitrogen atoms in the compound. Ammonium carbonate has a molar mass of 96.08 grams per mole. There are two nitrogen atoms in ammonium carbonate which is equal to 28.02 grams per mole. Divide the molar mass of nitrogen to the ammonium carbonate, 28.02/96.08 x 100, we get 29.16wt% nitrogen.

6 0
3 years ago
A nuclear waste site. cesium-137 is a particularly dangerous by-product of nuclear reactors. it has a half-life of 30 years. it
hram777 [196]
The mass decay rate is of the form
m(t) = m_{0} e^{-kt}
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.

Because the half-life is 30 years, therefore
e^{-30k} =  \frac{1}{2} \\\ -30k = ln(0.5) \\ k =  \frac{ln(0.5)}{-30} =0.0231

After 60 years, the mass remaining is
m = 3000 e^{-0.0231*60} = 750 \, g

Answer: 750 g

4 0
3 years ago
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