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Mashutka [201]
3 years ago
5

The dirigible Hindenburg had 3.7E6 m3 of hydrogen in its gas bags at 1.1 atm and 7°C. What was the weight of the hydrogen in pou

nds?
Chemistry
1 answer:
zepelin [54]3 years ago
4 0
Assuming that the gas is ideal, we can use the ideal gas equation PV=nRT to calculate for the number of moles. Then, multiply the molar mass of the gas to obtain the mass. We do as follows:

PV = nRT
n = PV / RT
n = 1.1 atm (3.7x10^9 L) / 0.08205 L-atm/mol-K (280.15) = 177061931.3 mol H2

Mass = (177061931.3 mol H2) 18.02 g/mol ( 1 kg / 1000g) ( 2.2 lb / 1 kg ) = 7019443.21 lb H2
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Juliette [100K]

Answer:

9.55 grams of SiO2

Explanation:

If the mass you mean by grams:

0.159 mole x 60.08 g (Periodic table by adding both elements)

Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:

9.55 grams of SiO2

4 0
3 years ago
A 25.0g piece of aluminum sits in a room and cools. It loses 4300.0 J of heat. If the initial temperature of aluminum is 125.3°C
Vesna [10]

Answer:

-65.8C

Explanation:

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5 0
3 years ago
2 NO + O22 NO2 is second order in NO and first order in O2. Complete the rate law for this reaction in the box below. Use the fo
riadik2000 [5.3K]

Answer : The value of rate of reaction is 1.35\times 10^{-8}Ms^{-1}

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given chemical equation is:

2NO+O_2\rightarrow 2NO_2

Rate law expression for the reaction is:

\text{Rate}=k[NO]^a[O_2]^b

As per question,

a = order with respect to NO  = 2

b = order with respect to O_2 = 1

Thus, the rate law becomes:

\text{Rate}=k[NO]^2[O_2]^1

Now, calculating the value of rate of reaction by using the rate law expression.

Given :

k = rate constant = 9.87\times 10^3M^{-2}s^{-1}

[NO] = concentration of NO = 7.86\times 10^{-3}M

[O_2] = concentration of O_2= 2.21\times 10^{-3}M

Now put all the given values in the above expression, we get:

\text{Rate}=(9.87\times 10^3M^{-2}s^{-1})\times (7.86\times 10^{-3}M)^2\times (2.21\times 10^{-3}M)^1

\text{Rate}=1.35\times 10^{-8}Ms^{-1}

Hence, the value of rate of reaction is 1.35\times 10^{-8}Ms^{-1}

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3 years ago
A solid forms when the average energy of a substance's particles
Dahasolnce [82]
<span>Matter is composed of particles that have kinetic energy. Particles with greater kinetic energy tend form liquids or gases due to increased rates of activity of the particles. Particles with lower energy tend to form solids. So, a solid forms when the average energy of a substance's particles decreases.</span>
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