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3 years ago

Explain how can you use base ten blocks to find 2.16 divided by 3

2 answers:

6 0

<span>For this question, let's move the decimal number 2 spaces to the right. 2.16-->216 You need 21 ten rods and 6 cubes. Why: I wouldn't do 2 hundred flats because 2 isn't divisible by 3. Put the ten rods into 3 equal group, then do the same with the cubes. You should end up with 7 in each group since 21 divided by 3 is 7. You should also end up with 2 cubes in each group. So in one group you have 72. Now move the decimal back to where it came from, 2 spaces to the left. Now you have 0.72.
</span>

egoroff_w [7]3 years ago

3 0

The answer is 0.72 because you divide 2.18 by 3 OR You can set the amount of blocks (2.16) out 3 times and count all of them up and that's your answer

Hope it Helps!!
Good Luck:)

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3 years ago

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Step-by-step explanation:

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2 years ago

I BET NO ONE KNOWS THIS Place a checkmark next to each answer choice that describes a situation in which economic indicators mig

Arada [10]

Answer:

E, F, B, and C

Step-by-step explanation:

Im just learning about these kind of things and this is a challenging question not going to lie.

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C seems like a good answer also because writing about economic trends is an important thing in economics. This also helps others learn out the economy and what not to do and what to do to help make our environment a better place.

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3 years ago

Suppose that you take a sample of 250 adults. If the population proportion of adults who watch news videos is 0.58, what is the

aliina [53]

Answer:

0.36% probability that fewer than half in your sample will watch news videos

Step-by-step explanation:

To solve this question, i am going to use the binomial approximation to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 250, p = 0.58$

$\mu = E(X) = 250*0.58 = 145$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{250*0.58*0.42} = 7.80$

If the population proportion of adults who watch news videos is 0.58, what is the probability that fewer than half in your sample will watch news videos

Half: 0.5*250 = 125

Less than half is 124 or less

So this is the pvalue of Z when X = 124

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{124 - 145}{7.8}$

$Z = -2.69$

$Z = -2.69$ has a pvalue of 0.0036

0.36% probability that fewer than half in your sample will watch news videos

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3 years ago

Read 2 more answers

Premises: All good students are good readers. Some math students are good students. Conclusion: Some math students are good read

just olya [345]

Answer:

Therefore, the conclusion is valid.

The required diagram is shown below:

Step-by-step explanation:

Consider the provided statement.

Premises: All good students are good readers. Some math students are good students.

Conclusion: Some math students are good readers.

It is given that All good students are good readers, that means all good students are the subset of good readers.

Now, it is given that some math students are good students, that means there exist some math student who are good students as well as good reader.

Therefore, the conclusion is valid.

The required diagram is shown below:

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3 years ago