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1 year ago

-7πh = 98π solve for h

Mathematics

2 answers:

ICE Princess25 [194]1 year ago

5 0

Answer:

h = -14

Step-by-step explanation:

-7πh = 98π

⇔ -7h = 98 (Just Divide both sides by π)

⇔ h = 98 ÷ (-7) = -14

ELEN [110]1 year ago

5 0

Hi :)

We should find h. All it takes is some algebra skills ^•^

First off, you can see than we have π on both sides. So, why not divide both sides by π and get it out of the way?

We end up with

$\boldsymbol{-7h=98}$

Super! Now all we have to do is divide both sides by -7

We end up with

$\boldsymbol{h=-14}$

$\tt{Learn~More;Work~Harder}$

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A drug company developed a new formula for their headache medication. To test the effectiveness of this new formula, 250 people

irina1246 [14]

Answer: correct is B

Step-by-step explanation:

Annex the bar graph that shows which improvement time is less, the new formula being more effective, with an average of 55 minutes and the average of the old formula is 75 minutes, which leads to the conclusion that the new formula is better than the previous one with a time difference of 20 minutes.

5 0

4 years ago

The length of a picture is 15.75 inches shorter than twice the width. If the perimeter of the picture is 106.5 inches, find its

Vladimir79 [104]

Answer:

Length = 45.37 in

Width = 30.56 in

Step-by-step explanation:

Let the width of the picture be 'w' inches.

Given:

Perimeter of the picture is, $P=106.5\ in$

Length is 15.75 inches shorter than twice the width. So, length is:

$l=2w-15.75$

Now, we know that the perimeter of a rectangular shape is given as the sum of all of its side. So, the picture is also of rectangular shape and hence the perimeter is given as:

$P=2l+2w$

Plug in the values of 'l' and 'P' and solve for 'w'. This gives,

$106.5=2w-15.75+2w\\106.5=4w-15.75\\106.5+15.75=4w\\4w=122.25\\w=\frac{122.25}{4}=30.56\ in$

Therefore, the width of the rectangular picture is 30.56 inches.

Length of the picture is, $l=2(30.56)-15.75=61.12-15.75=45.37\ in$

So, length of the picture is 45.37 inches and width is 30.56 inches.

3 0

3 years ago

3(8+9) there is nothing

astra-53 [7]

Answer:

Step-by-step explanation:

3(8+9) = Parenthesis
3(17) = Multiplication
51

5 0

3 years ago

Abby filled her goodie bags with 4 cookies and 3 candy bars and spent a total of $10.25 per bag. Marissa filled her goodie bags

Paladinen [302]

Let's start by writing a system of linear equations:
c -> cookies
cb -> candy bars
(You can use any abbreviations to your preference)

Abby:
4 cookies
3 candy bars
$10.25 per bag
The equation would be:
4c+ 3cb = $10.25

Marissa:
2 cookies
7 candy bars
$14.75 per bag
The equation would be:
2c + 7cb = $14.75

So our linear equation system would be:
<span>4c+ 3cb = $10.25
</span><span>2c + 7cb = $14.75

I would try to get rid of one variable so I can solve for the other variable. In this case, it is easier to get rid of c since I can multiply the second equations by 2. Then it would subtract the two equations.

(2c + 7cb = $14.75) 2 = 4c + 14 cb = $29.50

4c + 3cb = $10.25
   - 4c+14 cb = $29.50    (4c would get canceled.)
---------------------------------
   -11 cb = - $19.25    (Divide by -11 to solve for cb)
</span>    --------- -------------
-11 -11

   cb = $1.75

Now we know cb (candy bar) cost, we would substitute this value into cb into one of the equations. It doesn't matter which equation you put it in. I will substitute it in the first equations.

4c + 3 (1.75) = $10.25
4c + 5.25 = $10.25 (Multiply 3 by 1.75)
   -5.25 -5.25 (Subtract 5.25 on both sides)
   4c = 5 (Divide by 4 on both sides to get c)
   ---- ---
4    4

   c= 1.25

Check the work:
4(1.25) + 3(1.75)
= $10.25

2(1.25) + 7(1.75)
   = $14.75

Total cost:
cookies = $1.25
candy bars = $ 1.75

Hope this helps! :)

6 0

4 years ago

2) Here are two relations defined on the set {a, b, c, d): S= { (a, b), (a, c), (c, d), (c, a)} R={ (b, c), (c, b), (a, d), (d,

Dovator [93]

Answer:

Given relations defined on the set {a, b, c, d},

S= { (a, b), (a, c), (c, d), (c, a)}

R={ (b, c), (c, b), (a, d), (d, b)},

Since, SoR(x) = S(R(x)),

So, SoR(a) = S(R(a)) = S(d) = ∅,

SoR(b) = S(R(b)) = S(c) = d and a,

SoR(c) = S(R(c)) = S(b) = ∅,

SoR(d) = S(R(d)) = S(b) = ∅,

Thus, SoR = { (b,d), (b,a) }

RoS(a) = R(S(a)) = R(b) = c and RoS(a) = R(S(a)) = R(c) = b,

RoS(b) = R(S(b)) = R(∅) = ∅,

RoS(c) = R(S(c)) = R(d) = b and RoS(c) = R(S(c)) = R(a) = d

RoS(d) = R(S(d)) = R(∅) = ∅,

Thus, RoS = { (a, c), (a, b), (c,d), (c, b) },

SoS(a) = S(S(a)) = S(b) = ∅ and SoS(a) = S(S(a)) = S(c) = d and a

SoS(b) = S(S(b)) = S(∅) = ∅,

SoS(c) = S(S(c)) = S(d) = ∅ and SoS(c) = S(S(c)) = S(a) = b and c

SoS(d) = S(S(d)) = S(∅) = ∅,

SoS = { (a, d), (a, a), (c, b), (c, c) }

7 0

3 years ago