Answer:
0.25
Step-by-step explanation:
We have a total of ten student, and three students are randomly selected (without replacement) to participate in a survey. So, the total number of subsets of size 3 is given by 10C3=120.
On the other hand A=Exactly 1 of the three selected is a freshman. We have that three students are freshman in the classroom, we can form 3C1 different subsets of size 1 with the three freshman; besides B=Exactly 2 of the three selected are juniors, and five are juniors in the classroom. We can form 5C2 different subsets of size 2 with the five juniors. By the multiplication rule the number of different subsets of size 3 with exactly 1 freshman and 2 juniors is given by
(3C1)(5C2)=(3)(10)=30 and
Pr(A∩B)=30/120=0.25
.44 is the correct answer
C.i need help...
sana masagutan nio po yan...
Answer: yes it is indeed your very smart
Answer:
−27u + 8v
Explanation:
−3(4u − v) − 5( − v + 3u)
[ Distribute ]
= (−3)(4u) + (−3)(−v) + (−5)(−v) + (−5)(3u)
= −12u + 3v + 5v + −15u
[ Combine Like Terms ]
= −12u + 3v + 5v + −15u
= (−12u + −15u) + (3v + 5v)
= −27u + 8v
- PNW
