I don’t know sorry! ⚠️⚠️ but I hope that you can find the answer
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
921
Step-by-step explanation:
If he recives 3x amount than his oppenent
than we would divided by 3 from his score to find oppponets score
so....
2763 divided by 3=921
Answer:
i think... x=6
Step-by-step explanation:
3x+9=x+21
3x−x=12
2x=12
x=6
Answer:
The graph in the attached figure
Step-by-step explanation:
we know that
The equation of a vertical parabola in vertex form is equal to

where
a is a coefficient
(h,k) is the vertex
In this problem we have
(h,k)=(1,-4)
substitute

we have
An x-intercept of (-1,0)
substitute and solve for a




The equation is

<u><em>Verify the y-intercept</em></u>
For x=0


The y-intercept is the point (0,-3) -----> is correct
using a graphing tool
see the attached figure