Number 2 is $4 not $.40 and 3 is 10% OFF not added to. Those are all I had time to check but 1 is right
8 peaches. 8 peaches because if effie ate 4 peaches, or half of the bag, you would have to multiply 4 by 2 to get the answer of 8 peaches. mark brainliest please!
Answer:
240,000
Step-by-step explanation:
yeet
Answer:
8n
Step-by-step explanation:
The product of n and 8 means you will multiply n and 8. So, n x 8 is 8n.
Welcome to Brainly!
Binomial Theorem will follow this pattern:
The powers start at 3 and decrease down to 0 for the first term,
and start at 0 and increase to 3 for the other term.
(2x+4)^3 =
![\rm \_\_(2x)^34^0+\_\_(2x)^24^1+\_\_(2x)^14^2+\_\_(2x)^04^3](https://tex.z-dn.net/?f=%5Crm%20%5C_%5C_%282x%29%5E34%5E0%2B%5C_%5C_%282x%29%5E24%5E1%2B%5C_%5C_%282x%29%5E14%5E2%2B%5C_%5C_%282x%29%5E04%5E3)
See how the power counts down on the (2x)
and counts up on the 4?
That's the pattern that our expansion must follow.
I left a little space in front of each term.
The coefficient in front of each term will come from the fourth row of Pascal's Triangle. The one that looks like this:
1 3 3 1
Those are the coefficients we want:
![\rm 1(2x)^34^0+3(2x)^24^1+3(2x)^14^2+1(2x)^04^3](https://tex.z-dn.net/?f=%5Crm%201%282x%29%5E34%5E0%2B3%282x%29%5E24%5E1%2B3%282x%29%5E14%5E2%2B1%282x%29%5E04%5E3)
We can clean this up a little bit by getting rid of some of the junk. Anything to the 0th power is 1. So let's suppress all of our 1's because multiplying by 1 is not important.
![\rm (2x)^3+3(2x)^24+3(2x)4^2+4^3](https://tex.z-dn.net/?f=%5Crm%20%282x%29%5E3%2B3%282x%29%5E24%2B3%282x%294%5E2%2B4%5E3)
Now apply exponent rule, distributing the power to both the 2 and the x where applicable.
![\rm 2^3x^3+3\cdot2^2x^24+3\cdot2x4^2+4^3](https://tex.z-dn.net/?f=%5Crm%202%5E3x%5E3%2B3%5Ccdot2%5E2x%5E24%2B3%5Ccdot2x4%5E2%2B4%5E3)
Remember, multiplication is COMMUTATIVE, meaning we can multiply things in any order. So let's bring the numerical portion to the front of each term and multiply it all out.
![\rm 2^3x^3+3\cdot2^2\cdot4x^2+3\cdot2\cdot4^2x+4^3](https://tex.z-dn.net/?f=%5Crm%202%5E3x%5E3%2B3%5Ccdot2%5E2%5Ccdot4x%5E2%2B3%5Ccdot2%5Ccdot4%5E2x%2B4%5E3)