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2 years ago

The cost of renting a car is $39 plus $0.75 per mile. Which type of

Mathematics

2 answers:

Dima020 [189]2 years ago

6 0

Answer:

linear

Step-by-step explanation:

We can write this in the form

y = mx+b

where m is the .75 per mile and b is the 39 dollars

y = .75x + 39

tresset_1 [31]2 years ago

4 0

Linear. It is an additional constant charge per mile.

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Over the weekend, I bought a dress for $23.96, a pair of

Inga [223]

Answer:

4.94

Step-by-step explanation:

6 0

3 years ago

Fran baked 300 cookies for her bakery.15% of the cookies were oatmeal raisin.25% were snickerdoodle and the rest were chocolate

Masteriza [31]

Answer:

180

Step-by-step explanation:

15% of 300 is 45.

25% of 300 is 75.

45+75 is 120.

300-120 is 180

5 0

3 years ago

What is the probability of pulling out a red marble then a blue marble?

statuscvo [17]

Answer:

Step-by-step explanation:

Total marble = 8+5+4 = 19

n(Y) = 8, n(B) = 4 and n(R) = 5

Prob(R) = 5/17

Prob(B) = 4/16 {one marble is pulled out already}

Prob(R and B) = 5/17 × 4/16

= 5/17 × 1/4

= 5/68

5 0

2 years ago

(10.02)

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

2 years ago

A car is driving away from a crosswalk. The formula d = t2 + 2t expresses the car's distance from the crosswalk in feet, d, in t

alukav5142 [94]

Answer:

8 feet per second.

Step-by-step explanation:

We have been given that a car is driving away from a crosswalk. The formula $d=t^2+2t$ expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.

We will use average change formula to solve our given problem.

$\text{Average change}=\frac{f(b)-f(a)}{b-a}$

$\text{Average change}=\frac{d(5)-d(1)}{5-1}$

$\text{Average change}=\frac{(5)^2+2(5)-((1)^2+2(1))}{4}$

$\text{Average change}=\frac{25+10-(1+2)}{4}$

$\text{Average change}=\frac{35-3}{4}\\\\\text{Average change}=\frac{32}{4}\\\\\text{Average change}=8$

Therefore, the the car's average speed over the given interval of time would be 8 feet per second.

8 0

3 years ago