Question

What is the equilibrium expression for 2SO3(g) 0₂(g) +2SO₂(g)

Answer 1

Answer:

$K_{c} =\frac{[O_{2} ] [SO_{2} ]^{2} }{[SO_{3} ]^{2} }$

Explanation:

To construct the equilibrium constant, you need the balanced equation:

2 SO₃(g) -----> O₂(g) + 2 SO₂(g)

The equilibrium constant compares the concentrations of the products and the reactants.

The given expression follows this structure:

aA(g) ----> bB(g) + cC(g)

In this equation, the uppercase letters symbolize the molecules and the lowercase letters symbolize their corresponding coefficients in the balanced equation.

The general equilibrium expression looks like this:

$K_{c} =\frac{[B]^{b} [C]^{c} }{[A]^{a} }$

To be clear, the concentrations in the numerator represent the gaseous products and the concentrations in the denominator represent the gaseous reactants.

Therefore, the equilibrium expression for this equation is:

$K_{c} =\frac{[O_{2} ] [SO_{2} ]^{2} }{[SO_{3} ]^{2} }$