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NARA [144]
2 years ago
10

What is the ph of a solution of 0.450 m kh2po4, potassium dihydrogen phosphate?

Chemistry
1 answer:
iVinArrow [24]2 years ago
8 0
PKa = -log (Ka) = log [HPO4(2-)] - log[H+]^2 = - log(4.2×10^-13)
pH = - log [H+]
- log [H+]^2 = - 2 log [H+]
2pH = - log (4.2×10^-13) - log [HPO4(2-)]
2pH = - log (4.2×10^-13) - log (0.550)
pH = 6.32

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Why is the brcl molecules polar??
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Explanation:

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Answer:

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b. Na₂O + H₂O ⇒ 2 NaOH (óxido de sodio + agua ⇒ hidróxido de sodio)

Explanation:

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