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Elenna [48]
3 years ago
8

If sulfer undergoes alpha decay,what will it become?

Chemistry
1 answer:
olga_2 [115]3 years ago
7 0
S-34 is stable. It will not decay. @ answers.com this is also a good site to find the answer to your questions.
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Which equation expresses the solubility product of Zn3(PO4)2?
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How many moles of solute are present in 150mL of 0.30 mol/L NaOH solution
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Answer: n= 0.045 mol

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Soil particles, soot, lead (pb), asbestos, sea salt, and sulfuric acid droplets are all types of?
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2 years ago
1. First Experiment: Thomson directed the beam at an electrometer and tried to separate the
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4 0
3 years ago
The rate law for 2NO(g) + O2(g) ====&gt;2NO2(g) is rate=k[NO]^2[O2]. In addition to the mechanism, the following have been propo
pishuonlain [190]

Answer:

Mechanism (I).    

Explanation:

<em>The given chemical reaction</em><em>: </em>

2NO(g) + O₂(g) → 2NO₂(g)

<em>The given rate equation for the reaction</em><em>:</em>

rate = k [NO]² [O₂]  

The rate equation of a given chemical reaction is equal to the product of the concentration of reactants raised to the power the partial orders of reaction.

The overall rate of a given multi-step chemical reaction depends on the slowest step in the reaction mechanism.

Therefore, the slowest step of a given chemical reaction is called the rate-determining step (RDS).

<em>The proposed reaction mechanisms:</em>

(I). 2NO(g) + O₂(g) → 2NO₂(g)

In an elementary (single step) reaction, the rate equation can be written as:

rate = k [NO]² [O₂]

(II). 2NO (g) ===> N₂O₂ (g) [fast]

N₂O₂(g) +O₂(g) ===> 2NO₂ (g) [slow] ⇒ RDS

In an complex (multi-step) reaction, the slow step is the rate determining step (RDS). So, the rate equation can be written as:

rate = k [N₂O₂] [O₂]

(III). 2NO(g) ===>N₂(g) + O₂(g) [fast]

N₂(g) + 2O₂(g) ===> 2NO₂(g) [slow] ⇒ RDS

In an complex (multi-step) reaction, the slow step is the rate determining step (RDS). So, the rate equation can be written as:

rate = k [N₂] [O₂]²

<em>Thus, the rate equation of the reaction mechanism: (I). is the same as the given rate law of the chemical reaction.</em>

<u>Therefore, reaction mechanism (I). is consistent with the rate law of the given chemical reaction.</u>

7 0
3 years ago
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