Answer:
V₂ = 4.7 L
Explanation:
Given data:
Initial volume = 5.0 L
Initial pressure = 1.50 atm
Final pressure = 1240 mmHg (1240/760 = 1.6 atm)
Final volume = ?
Solution:
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = 1.50 atm ×5.0 L/1.6 atm
V₂ = 7.5 atm. L /1.6 atm
V₂ = 4.7 L
B is the answer..!
Disturbance is in a circular motion
Answer:
The volume of 0.0256 gram of H₂s is =0.0178944 liter
Explanation:
Specific volume of H₂S is 0.699 m³/kg
The volume of 1000 gram of H₂s is 0.699 m³
Then the volume of 0.0256 gram of H₂s is =![\frac{0.699\times 0.0256}{1000}](https://tex.z-dn.net/?f=%5Cfrac%7B0.699%5Ctimes%200.0256%7D%7B1000%7D)
= 0.000178944 m³
=0.000178944×1000 l
=0.0178944 liter
Answer:
Explanation:
The final net force will be in the Z- direction. Let's find out the z component of the force on the differential volume of charge is:
df = dqEcosθz
![E = \frac{1}{4\pi epsilon} \frac{Qr}{R^{3} }](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B4%5Cpi%20epsilon%7D%20%5Cfrac%7BQr%7D%7BR%5E%7B3%7D%20%7D)
dq = ρdV = ![\frac{3Q}{4\pi R^{3} }](https://tex.z-dn.net/?f=%5Cfrac%7B3Q%7D%7B4%5Cpi%20R%5E%7B3%7D%20%7D)
dr.sinθdθdΦ
integrate it over half ball,
.sinθcosθdθdΦ.( these are part of the integral, i was unable to write it in equation format).
=
sinθcosθdθ
= ![\frac{3Q^{2} }{64\pi epsilon R^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B3Q%5E%7B2%7D%20%7D%7B64%5Cpi%20epsilon%20R%5E%7B2%7D%20%7D)
![F = \frac{3Q^{2} }{64\pi epsilon R^{2} } z](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B3Q%5E%7B2%7D%20%7D%7B64%5Cpi%20epsilon%20R%5E%7B2%7D%20%20%7D%20z)
Answer:
Chemical reactions often involve changes in energy due to the breaking and formation of bonds. Reactions in which energy is released are exothermic reactions, while those that take in heat energy are endothermic.
Explanation: