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Firdavs [7]
3 years ago
15

In a candy mix there are 4 green bars for every 3 red bars. How many red bars are there if there are 200 green bars?

Mathematics
2 answers:
vekshin13 years ago
8 0
4 Green bars = 3 Red bars 

200 Green bars = 150 Red bars
____________________________________

200/4 = 50

50 x 3 = 150

or 

You simply take 3/4 of whatever the value of green bars.
UkoKoshka [18]3 years ago
3 0

150 red bars

4/3=200/150

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Read 2 more answers
Recall that in the problem involving compound interest, the balance A for P dollars invested at rate r for t years compounded n
RoseWind [281]

Answer:

(a)∴A=$6753.71.

(b)∴A=$1480.24

(c) ∴P=$7424.70

(d)∴P=$49759.62

(e)∴P=$5040.99

(f) ∴P=$2496.11

Step-by-step explanation:

We use the following formula

A=P(1+\frac rn)^{nt}

A=amount in dollar

P=principal

r=rate of interest

(a)

P=$2,500, r=5%=0.05,t =20 years , n= 4

A=\$2500(1+\frac{0.05}{4})^{(20\times 4)

   =$6753.71

∴A=$6753.71.

(b)

P=$1,000, r=8% =0.08,t =5 years , n= 2

A=\$1000(1+\frac{0.08}{2})^{(5\times 2)

   =$1480.24

∴A=$1480.24

(c)

A=$10,000, r=6% =0.06,t =5 years , n= 4

10000=P(1+\frac{0.06}{4})^{(5\times 4)}

\Rightarrow P=\frac{10000}{(1+0.015)^{20}}

\Rightarrow P=7424.70

∴P=$7424.70

(d)

A=$100,000, r=6% =0.06,t =10 years , n= 12

100000=P(1+\frac{0.07}{12})^{(10\times 12)}

\Rightarrow P=\frac{100000}{(1+\frac{0.07}{12})^{120}}

\Rightarrow P=49759.62

∴P=$49759.62

(e)

A=$100,000, r=10% =0.10,t =30 years , n= 12

100000=P(1+\frac{0.10}{12})^{(30\times 12)}

\Rightarrow P=\frac{100000}{(1+\frac{0.10}{12})^{360}}

\Rightarrow P=5040.99

∴P=$5040.99

(f)

A=$100,000, r=7% =0.07,t =20 years , n= 4

100000=P(1+\frac{0.07}{4})^{(20\times 4)}

\Rightarrow P=\frac{100000}{(1+\frac{0.07}{4})^{80}}

\Rightarrow P=2496.11

∴P=$2496.11

6 0
3 years ago
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