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Alla [95]
1 year ago
5

An indicator with a lower pka will have a color change interval that is _____ on the ph scale.

Chemistry
1 answer:
Ulleksa [173]1 year ago
5 0

An indicator with a lower pka will have a color change interval that is base on the ph scale.

Since indicators are weak acids or bases, they change form as the pH fluctuates. When the indicator's pKa and pH are numerically equal, the indicator will be composed of 50% acid and 50% basic forms. One unit higher in pH results in 10% acid form and 90% basic form. As a result, there occurs a progressive switch from almost exclusively acid to almost exclusively base form.

As the ratio of acid to base changes, the colour of the indicator also changes because indicators come in both acid and basic forms. For our eyes to see a colour as pure red or pure yellow, for example, a ratio of roughly 10:1 is typically required.

The precise ratio will depend on the compound's absorbance and how sensitive our eyes are to a particular colour. However, we will typically observe a change over a pH range of about 2 from pKa -1 (90% acid) to pKa +1 (90% basic).

Learn more about indicator here;
brainly.com/question/8876896

#SPJ4

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Uranium has an atomic weight of 238 amu.
shepuryov [24]

Answer:

U= 238g/mol

U2O5= 556g/mol

Explanation:

Since U= 238

O=16

U3O5= 2(238)+3(16)=556g/mol

4 0
3 years ago
The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the
IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

Explanation :

The expression for first order reaction is:

[C_t]=[C_o]e^{-kt}

where,

[C_t] = concentration at time 't'  (final) = ?

[C_o] = concentration at time '0' (initial) = 0.100 M

k = rate constant = 5.40\times 10^{-3}s^{-1}

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}

[C_t]=4.05\times 10^{-4}M

Thus, the concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

4 0
3 years ago
A 25.0 L tank of nitrogen gas is at 25 oC and 2.05 atm . If the temperature stays at 25 oC and the volume is decreased to 14.5 L
NeTakaya

Answer:

\boxed {\boxed {\sf P_2 \approx 3.53 \ atm}}

Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

P_1V_1=P_2V_2

Now we can substitute any known values into the formula.

Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

25.0 \ L * 2.05 \ atm = P_2V_2

The volume is decreased to 14.5 liters, but the pressure is unknown.

25.0 \ L * 2.05 \ atm = P_2 * 14.5 \ L

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}=\frac{P_2 *14.5 \ L}{14.5 \ L}

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}= P_2

The units of liters cancel.

\frac {25.0  * 2.05 \ atm }{14.5 }=P_2

\frac {50.25\  atm }{14.5 }=P_2

3.53448276 \ atm = P_2

The original values of volume and pressure have 3 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 3.53448276

The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

3.53 \ atm \approx P_2

The new pressure is approximately <u>3.53 atmospheres.</u>

8 0
3 years ago
Are mass and *weight of matter* the same thing​
Scorpion4ik [409]

Answer:

Mass is the quantity of an object.

Weight is the force with which the object is attached towards the earth.

Hope it helps

7 0
3 years ago
Read 2 more answers
What is the limiting reactant in the following equation? How much Fe2O3 will be produced if 2.1 g of Fe with 2.1 g of O2?
Verizon [17]

Answer:

Fe is limiting, and it will produce .0188 mols of Fe2O3

Explanation:

after you convert both Fe and O2 to mols by using their molar mass, you see there is less Fe than O2 so that is your limiting reactant. To find the amount of Fe2O3 you devide the limiting reactant by it's coefeciant (4) then multiply it by the products coefficant (2). Let me know if you have any questions

8 0
3 years ago
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