What is the definition of a chemical bond
1 answer:
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Answer:
HI (hydrogen iodide).
Explanation:
Hello,
In this case, since iodine is in group VIIA, it has seven valence electrons at its outer shell, which means that it only needs one bond to attain the octet. Moreover, since hydrogen has just one electron at its outer shell, one hydrogen turns out enough to obey the octet when hydrogen and iodine bond as shown below:
Therefore, the required formula is:
Which is hydrogen iodide.
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Answer:
a) Q = 6.1875x10⁻³
b) The direction of the reaction is to form the products.
c) [Cl₂]e = 0.094 M
[NO]e = 0.190 M
[NOCl]e = 0.140 M
Explanation:
a) Q is the reaction quotient, and for a generic reaction aA + bB ⇄ cC + dD it is
Which is the same equation for Kc, but in Kc expressions, the concentrations are in the equilibrium. Q is calculated at any time. So, for the reaction given
2NOCl(g) ⇄ 2NO(g) + Cl2(g)
[Cl₂] = 0.220/5.00 = 0.044 M
[NO] = 0.450/5.00 = 0.090 M
[NOCl] = 1.20/5.00 = 0.240 M
Q = (0.044)x(0.090)²/(0.240)²
Q = 6.1875x10⁻³
b) Q < Kc, which means that there are fewer products to what are needed to the equilibrium. So the direction of the reaction is to form the products.
c)
2NOCl(g) ⇄ 2NO(g) + Cl2(g)
0.240 0.090 0.044 <em>Initial</em>
-2x +2x +x <em> Reacts</em> (stoichiometry is 2:2:1)
0.240-2x 0.090+2x 0.044+x <em> Equilibrium</em>
3.564x10⁻⁴+0.01584x+0.176x²+8.1x10⁻³x+0.36x²+4x³ = 0.010714-0.17856x+0.744x²
4x³ - 0.208x² + 0.2025x - 0.01036 = 0
Solving this third grade equation in a computer program:
x = 0.05 M
So:
[Cl₂]e = 0.044 + 0.05 = 0.094 M
[NO]e = 0.090 + 2x0.05 = 0.190 M
[NOCl]e = 0.240 - 2x0.05 = 0.140 M