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3 years ago

What is the definition of a chemical bond

Chemistry

1 answer:

nlexa [21]3 years ago

4 0

The answer should be c I believe

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Rxn

givi [52]

Answer: The enthalpy of formation of $SO_3$ is -396 kJ/mol

Explanation:

Calculating the enthalpy of formation of $SO_3$

The chemical equation for the combustion of propane follows:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(O_2(g))})]$

We are given:

$\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-297kJ/mol\\\Delta H^o_{rxn}=-198kJ$

Putting values in above equation, we get:

$-198=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta -297)+(1\times (0))]\\\\\Delta H^o_f_{(SO_3(g))}=-396kJ/mol$

The enthalpy of formation of $SO_3$ is -396 kJ/mol

4 0

3 years ago

How do take off my question when I don't have a question?

kotegsom [21]

Why would you ask a question if you didnt have a question?

Just get someone to report it, and itll be deleted

7 0

3 years ago

Read 2 more answers

Write any two differences between autotrophs and heterotrophs . subject-science

jolli1 [7]

Answer:

Autotrophs are organisms that prepare their own food through the process of photosynthesis, whereas heterotrophs are organisms that cannot prepare their own food and depend upon autotrophs for nutrition.

Explanation:

Btw I searched this up found it on a website called byjus.com. Hope this helps!

3 0

3 years ago

Read 2 more answers

I need help with my quiz.

katrin2010 [14]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

How many liters of carbon dioxide will be produced at STP if 3.56 g calcium carbonate reacts completely with carbon dioxide? CaC

sp2606 [1]

Answer:

V = 0.798 L

Explanation:

Hello there!

In this case, for this gas stoichiometry problem, we first need to compute the moles of carbon dioxide via stoichiometry and the molar mass of starting calcium carbonate:

$3.56gCaCO_3*\frac{1molCaCO_3}{100gCaCO_3} *\frac{1molCO_2}{1molCaCO_3} =0.0356molCO_2$

Next, we use the ideal gas equation for computing the volume, by bearing to mind that the STP conditions stand for a pressure of 1 atm and a temperature of 273.15 K:

$PV=nRT\\\\V=\frac{nRT}{P}\\\\V=\frac{0.0356mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm} \\\\V=0.798L$

Best regards!

4 0

3 years ago