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Paraphin [41]
1 year ago
3

What is the necessary voltage to power the electrolysis of molten sodium chloride?

Chemistry
1 answer:
Neporo4naja [7]1 year ago
3 0

The necessary voltage to power the electrolysis of molten sodium chloride is 4V.

Electrolysis is the breakdown of a compound into the elements it is formed from by passing electricity through it. It is actually a chemical reaction in which one element loses electrons and the other may gain electrons. The process of electrolysis has wide applications in electroplating, metallurgical processes, production of chlorine gas, etc.

Molten sodium chloride is generally used in the production of chlorine gas and sodium metal. This molten or aqueous form of sodium chloride is also known as brine. The process is carried out in a cell called the Down's cell.

To know more about electrolysis, here

brainly.com/question/12054569

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Yuki888 [10]

Answer:

The electron took two jumps to return to its ground state.

Explanation:

If the electron is in nth state then it first goes to (n-1)th to 2nd state and emits one photon of this energy gap. Then, it goes to ground state and emits another photon of different energy. It can emit \left \{ {{n-1} \atop {2}} \right. types of different photons. Fourth option is incorrect because in that case it emits one photon and absorbs one photon to go back to that state and also both photons are of same energy.

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raketka [301]

Answer:

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3 years ago
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Ivahew [28]

Explanation:

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7 0
3 years ago
Which of the following is not a reason for creating hybrid plants?
Softa [21]
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6 0
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Read 2 more answers
Write a balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic aqueous solution. Be su
Vesna [10]

Answer:

Balanced half-reaction: O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)

Explanation:

Balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic solution should be written in the following step-by-step manner:

Half-reaction: O_{2}(g)\rightarrow H_{2}O_{2}(aq.)

Balance H and O in basic medium: O_{2}(g)+2H_{2}O(l)\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)

Balance charge: O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)

Balanced half-reaction: O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)

7 0
4 years ago
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