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Rudik [331]
4 years ago
5

Use the equation 2Cu+O2 —> 2CuO to find how many grams of copper react to form 3.64 mol CuO.

Chemistry
1 answer:
mylen [45]4 years ago
5 0
<h3>Answer:</h3>

231.31 g

<h3>Explanation:</h3>

<u>We are given;</u>

  • The mass of CuO produced as 3.64 moles
  • The equation fro the reaction as

2Cu+O2 → 2CuO

We are required to determine the mass of copper that would react.

  • In this case, we are going to use the concept on mole ratio.
  • From the balanced equation,

2 moles of Cu reacts with 1 mole of oxygen to yield 2 moles of CuO

  • Therefore, the mole ratio of copper (Cu) to CuO is 2: 2 or 1 : 1 (simplified)
  • Therefore;

Moles of Cu = moles of CuO

Thus, moles of Cu = 3.64 moles

But, Mass = Number of moles × atomic mass

Atomic mass of copper = 63.546

Thus,

Mass of Cu = 3.64 moles × 63.546 g/mol

                   = 231.31 g

Thus, 231.31 g of copper will react to produce 3.64 moles of CuO

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sattari [20]

A Cell with few energy needs would most likely contain a small number of Mitochondria.

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  • They transform glucose into ATP, a chemical with a huge energy storage capacity.
  • Muscles have a large number of mitochondria, allowing them to react rapidly and powerfully to the body's ongoing need for energy.
  • Macromolecules, defunct cell components, and microbes are all digested by lysosomes.
  • Vacuoles are typically tiny and aid in the sequestration of waste.
  • The ribosome, an intercellular structure consisting of both RNA and protein, is where a cell produces new proteins.

Therefore out of all these cell organelles, the cell has fewer mitochondria for less energy need.

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5 0
2 years ago
Calculate the number of grams of CO that can react with 0.400 kg of Fe2O3.
aleksandr82 [10.1K]

Answer:

mass of CO = 210.42 g

mass in three significant figures = 210. g

Explanation:

Given data:

mass of Fe2O3 = 0.400 Kg

mass of CO= ?

Solution:

chemical equation:

Fe2O3 + 3CO → 2Fe + 3CO2

Now we will calculate the molar mass of  Fe2O3 and CO.

Molar mass of  Fe2O3 = (55.845 × 2) + (16 × 3) = 159.69 g/mol

Molar mass of CO = 12+ 16 = 28 g/mol

now we will convert the kg of Fe2O3 in g.

mass of Fe2O3 = 0.400 kg × 1000 = 400 g

number of moles of Fe2O3  = 400 g/ 159.69 g/mol = 2.505 mol

mass of CO = moles of Fe2O3 × 3( molar mass of CO)

mass of CO = 2.505 mol × 84 g/mol

mass of CO = 210.42 g

mass in three significant figures = 210. g

5 0
4 years ago
Read 2 more answers
26 g of zinc combines with 12.8 g of sulfur. What is the empirical formula of zinc sulfide?
Alisiya [41]
Moles of Zn: 26 / 65 = 0.4
Moles of S: 12.8 / 32 = 0.4

Molar ratio of Zn : S = 1 : 1
Empircal formula: ZnS

The answer is C
7 0
4 years ago
Can someone help me with #35,37,39,41 please
adoni [48]
35 b.
37 h
39 i
41 d
hope that helps
4 0
3 years ago
How much energy is needed to completely boil a 5.05g sample of water?
Keith_Richards [23]

Given what we know, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.

<h3>Why does it take this much energy to boil the water?</h3>

We arrive at this number by taking into account the energy needed to boil 1g of water to its vaporization point. This results in the use of 2260 J of heat energy. We then take this number and multiply it by the total grams of water being heated, in this case, 5.05g, which gives us our answer of 11.4 kJ of energy required.

Therefore, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.

To learn more about the behavior of water visit:

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8 0
3 years ago
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