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daser333 [38]
4 years ago
7

Write a balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic aqueous solution. Be su

re to add physical state symbols where appropriate.
Chemistry
1 answer:
Vesna [10]4 years ago
7 0

Answer:

Balanced half-reaction: O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)

Explanation:

Balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic solution should be written in the following step-by-step manner:

Half-reaction: O_{2}(g)\rightarrow H_{2}O_{2}(aq.)

Balance H and O in basic medium: O_{2}(g)+2H_{2}O(l)\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)

Balance charge: O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)

Balanced half-reaction: O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)

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How many grams of aluminum sulfate: Al2(SO4)3 , would be formed if 250 g of H2SO4 react with aluminum? The reaction is: 2Al + 3H
NikAS [45]

Answer:

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

Explanation:

Step 1: Data given

Mass of H2SO4 = 250 grams

Molar mass H2SO4 = 98.08 g/mol

Step 2: The balanced equation

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

Step 3: Calculate moles H2SO4

Moles H2SO4 = mass H2SO4 / molar mass H2SO4

Moles H2SO4 = 250 grams / 98.08 g/mol

Moles H2SO5 = 2.55 moles

Step 4: Calculate moles Al2(SO4)3

For 2 moles Al we need 3 moles H2SO4 to produce 1 mol Al2(SO4)3 and 3 moles H2

For 2.55 moles H2SO4 we'll have 2.55/3 = 0.85 moles Al2(SO4)3

Step 5: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass

Mass Al2(SO4)3 = 0.85 moles * 342.15 g/mol

Mass  Al2(SO4)3 = 290.8 grams

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

7 0
4 years ago
7. Which is an example of a good insulator? <br>iron<br>copper <br>silver <br>rubber​
Dmitrij [34]

Answer:

Rubber is an insulator.

Remaining three are metals and hence conductors.

4 0
3 years ago
Turn the word equation into a chemical balanced equation.
yan [13]
(2)KClO3 = (2)KCl + (3)O2

you have 2 Potassium Chlorates for every 2 Potassium Chlorides and 3 Oxygen
7 0
3 years ago
A small cup of water is left out on the counter. Three days later, the water is gone. Which phase change describes what has occu
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8 0
4 years ago
Read 2 more answers
Hydrogen gas and solid gold(III) sulfide are reacted. Pure solid gold metal is formed and gaseous hydrogen sulfide is released.
alexdok [17]

The reactants of the reaction will be solid gold (III) sulfide and hydrogen gas, while the products will be pure solid gold and hydrogen sulfide gas.

<h3>Chemical reactions</h3>

Reactants react together during reactions to arrive at products.

In this case, solid gold (III) sulfide and hydrogen gas react according to the following equation:

Au_2S_3(s) + 3 H_2 (g)-- > 2 Au(s) + 3H_2S(g)

Reactants = solid gold (III) sulfide, hydrogen gas

Products: pure solid gold, hydrogen sulfide gas

More on chemical reactions can be found here: brainly.com/question/1689737

8 0
2 years ago
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