Answer:
C. Ca.
Explanation:
The atom loses or gains electrons forming anion or cation to reach stability (fill the outermost shell of the electron levels).
When atom gains electrons forms anions with negative charge.
While, when atom loses electrons forms cations with positive charge.
A. O:
O atom has 8 electrons in its nucleus and gains 2 electrons to reach stability (10 electrons, configuration of Ne).
<em>So, it forms O²⁻.</em>
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B. AI:
Al atom has 13 electrons in its nucleus and loses 3 electrons to reach stability (10 electrons, configuration of Ne).
<em>So, it forms Al³⁺.</em>
<em></em>
C. Ca:
Ca atom has 12 electrons in its nucleus and loses 2 electrons to reach stability (10 electrons, configuration of Ne).
<em>So, it forms Ca²⁺.</em>
<em></em>
D. Na:
Na atom has 11 electrons in its nucleus and loses 1 electron to reach stability (10 electrons, configuration of Ne).
<em>So, it forms Na⁺.</em>
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Answer:
One single orbital can hold the maximum of 2 electrons.
Explanation:
The 2 electrons must have opposing spins otherwise they would have the same four quantum numbers, which is forbidden.
- One electron would spin up
- The other would spin down
This would tell us that each subshell would have double the electrons per orbital
1.16 g of UF₄ can be formed in this reaction.
<u>Explanation:</u>
We have to write the balanced equation of the reaction between Uranium oxide and hydrogen fluoride to form Uranium tetra fluoride and water as,
UO₂(s) +4 HF(aq) → UF₄ + 4 H₂O(l)
We can find the moles of UF₄ and then multiplying molar mass of UF₄ with the moles of UF₄, we will get the mass of UF₄ in grams.
Moles of UF₄ = 
= 0.00370 mol UF₄
Grams of UF₄ =0.00370 mol × 314.02 g/mol = 1.16 g of UF₄
So mass of UF₄ formed in the reaction is 1.16 g.
