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Contact [7]
1 year ago
6

T

Chemistry
1 answer:
Ksenya-84 [330]1 year ago
4 0

The change in free energy is 19.3kJ.

<h3>What is the equilibrium constant?</h3>

Now we know that the equation of the reaction is; H₂(g) + Cl₂(g)⇔2HCI(g).

Thus we have that Kp can only be obtained at equilibrium thus we ste up the ICE table as shown;

pH2 = 1 atm

pCl2 = 1 atm

pHCl =  16.30 mm Hg or 0.02 atm

        H₂(g) + Cl₂(g) ⇔ 2HCI(g)

I        1           1                0

C     -x           -x               +2x

E     1 - x         1 -x            2x

When 2x = 0.02

x = 0.01

pH2 =  1 - 0.01

pCl2 = 1 - 0.01

pHCl = 0.02

Kp = (0.02)^2/(0.99)^2

Kp = 4.1 * 10^-4

ΔG = -RT lnKp

ΔG = - (8.314 * 298.15 * ln  4.1 * 10^-4)

= 19.3kJ

Learn more about change in free energy:brainly.com/question/14039127

#SPJ1

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