Answer:
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Given parameters:
duration of fall = 6s
Unknown:
Speed of the rock before it hits the ground = ?
Solution:
To solve this problem, we apply one of the appropriate motion equations;
V = u + gt
Where V is the final velocity
u is the initial velocity
t is the time taken
g is the acceleration due to gravity = 9.8m/s²
The initial velocity is 0;
So;
V = gt
Input the parameters and solve for V;
V = 9.8 x 6 = 58.8m/s
The velocity before hitting the ground is 58.8m/s
To solve this problem, we begin by first calculating the area of the front lawn. The length and width of the lawn was given and the area of a rectangle is given by the formula: Area = length x width. Thus, the area of the front lawn can be obtained by multiplying 18 ft by 20 ft, wherein we get 360 ft^2 as the area.
Second, the problem indicated that each square foot of lawn accumulates 1450 new snow flakes per minute. This can be translated into the expression 1450 snow flakes/ (minute·ft^2). In this way, we can convert it to units of mass (kg). Afterwards, we simply need to multiply it to the area of the lawn and convert minute to hour. The following expression is then used:
1450 snow flakes/ (minute·ft^2) x 1.90 mg/snow flake x 1 g/1000 mg x 1kg/1000 g x 360 ft^2 x 60 minutes/hour = 59.508 kg snow flake/hour
It is then calculated that 59.508 kg of snow flake accumulates in the lawn every hour.
<span> Heterogeneous mixture because the components are not or can't be mixed uniformly..
Ex : Oil in water or Sand in water </span>