since the concentration of Carbon Dioxide will increase, it would make Q > K, cause equilibrium to shift in the direction with less moles of gas to alleviate the extra pressure. In this case, the reaction will shift left because there are fewer moles of gas present.
You have to put your attention to the unit of concentration. It is expressed in terms of molarity, which is represented in M. It is the number of moles solute per liter solution. So, you simply have to multiply the molarity with the volume in liters.
Volume = 275 mL * 1 L/1000 mL = 0.275 L
<em>Moles Ba(OH)₂ = (0.200 M)(0.275 L) = 0.055 mol</em>
Answer:
CO(g) + H2(g) + H2O(g) ==> CO2(g) + 2H2(g)
Explanation:
In the industry, hydrogen is prepared from water and hydrocarbons. Water gas being the major method of preparation of hydrogen industrially.
The water-gas reaction is an industrial process in which steam is passed over red-hot coke giving a gaseous mixture of carbon monoxide and hydrogen:
C + H2O(g) → CO + H2.
The mixture of CO and H2 is Futher passed through steam according to the equation:
CO(g) + H2(g) + H2O(g) ==> CO2(g) + 2H2(g) to give hydrogen and carbon dioxide.
I Think that the answer is 15.2096 Kilograms, but I might be wrong.
Answer:
m = E × Q
And Q = I × t
m = E × I × t
Where m = mass in grams
Q = quantity of electricity in coulomb
I = current in ampere
t = time in seconds
E = electrochemical equivalent of the substance
Explanation:
