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murzikaleks [220]
3 years ago
8

How to find reaction force

Chemistry
1 answer:
shtirl [24]3 years ago
8 0

Answer:

Let the sum of moments about a reaction point equal to ZERO (ΣM = 0) ...

Let the sum of vertical forces equal to 0 (ΣFy = 0)

Explanation:

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Ted likes to run long distances. He can run 20 km 20 km20, start text, space, k, m, end text in 95 9595 minutes. He wants to kno
balu736 [363]

Answer:

The distance in kilometer that Ted will go if he runs at the same pace for 285 minutes is 60km

Step-by-step explanation:

It was given that Ted Ted runs 20 km in 95 minutes, so for us to know how many kilometers he runs at the same pace for 285 minutes by using proportion.

For Ted to run 20 km in 95 minutes.

Speed=Distance/Time

where given distance= 20km

Given time =95minutes

Speed=20/95 .............eqn(1)

To calculate the distance in kilometers Ted will go if he runs at the same pace for 285 minutes, then

Speed= K/225 ...............eqn(2)

Let us represent distance with 'K'

Given time 225minutes

Equating eqn(1) and eqn(2)

Hence the proportion model that Ted could use in modelling this situation is this;

20/95=K/225

Cross multiply

K×95=20×225

K=60

The distance in kilometer that Ted will go if

he runs at the same pace for 285 minutes is 60km

3 0
4 years ago
What is the h2 h2o molar ratio??
lara31 [8.8K]
2molH2: 1molO2:2molH2O
6 0
3 years ago
If 852.04 g Al(NO3)3 reacted with the 741.93 g Na2CO3, which would be the limiting reagent?
Sedaia [141]

Answer:

Al(NO3)3

Explanation:

6 0
3 years ago
1. What is the Celsius Temperature Scale of K=303?
qaws [65]

Explanation:

303k -273k=30°c because 0°c is 273K

6 0
2 years ago
Read 2 more answers
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring
iren2701 [21]

Answer:

1.20 V

Explanation:

The standard cell potential is calculated from the expression

ε⁰ cell = ε⁰ oxidation + ε⁰  reduction

The species that will be reduced is the one with the higher standard reduction potential and the species that will be oxidized will be the one with the more negative reduction potential.

Thus for our question we will have

oxidation:

Pb(s)  →   Pb2+(aq) + 2 e-       ε⁰ oxidation       =  -   ε⁰  reduction

                                                                          =   - ( - 0.13 V ) = + 0.13 V

reduction    

Br2(l) + 2 e- → 2 Br-(aq)           ε⁰  reduction     = +1.07 V

ε⁰ cell = ε⁰ oxidation + ε⁰  reduction = + 0.13 V + 1.07 V  = 1.20 V

4 0
3 years ago
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