Answer:
MgCl2 > C4H9OH > CH4 > C3H8.
Explanation:
Alkanes do not form hydrogen bonds and are insoluble in polar solvents e.g water. The hydrogen bonds between water molecules are move away from an alkane molecule and this worsens as their Carbon chain / molecular weight increases.
MgCl2 is soluble in water. Water essentially breaks down the ionic crystal lattice and the resulting solution is slightly basic.
Alcohols are generally soluble in water and this is because of the -OH group and its ability to form hydrogen bonds with water molecules. As applied to alkanes, as the carbon chain in the alkyl group increases, the solubility decreases.
From the most soluble to the least soluble,
MgCl2 > C4H9OH > CH4 > C3H8.
Answer:
368.92g
Explanation:
Firstly, let's balance the equation which is
2NO + O₂ ---> 2NO₂
Starting with 8.02 mol of NO let's calculate the moles of oxygen which is in a 2 : 1 molar ratio
2NO + O₂
2 : 1
8.02 mol : x mol
Moles of O₂ = 8.02 ÷ 2 = 4.01 mol
Doing the same thing for 18.75 mol of O₂ to calculate the number of moles of NO
2NO + O₂
2 : 1
x mol : 18.75 mol
Moles of NO = 18.75 × 2 = 37.5 however we are told we have 8.02 moles of NO, so we are unable to use 18.75 mol of O₂
Using 8.02 mol of NO to figure out the number of moles of NO₂ :
2NO : 2NO₂
They have the same molar ratio of 2 : 2, so the number of moles is 8.02
Using formula moles = mass / Molar mass
Rearranging to find mass = moles × molar mass
Molar mass of NO₂ = 14 + 16 + 16 = 46
Mass = 46 × 8.02 = 368.92g
Hey there!
Ca + O₂ → CaO
Balance O.
2 on the left, 1 on the right. Add a coefficient of 2 in front of CaO.
Ca + O₂ → 2CaO
Balance Ca.
1 on the left, 2 on the right. Add a coefficient of 2 in front of Ca.
2Ca + O₂ → 2CaO
Our final balanced equation: 2Ca + O₂ → 2CaO
Hope this helps!
Answer:
1.02 grams
Explanation:
The reaction between Na₃PO₄ and BaCl₂ is:
2Na₃PO₄(aq) + 3BaCl₂(aq) → Ba₃(PO₄)₂(s) + 6NaCl(aq)
We need to find the number of moles of Na₃PO₄ and BaCl₂:
Now, we need to find the limiting reactant:
We have that it is needed 0.0033 moles of Na₃PO₄ to react with BaCl₂ and we have 0.01 moles of Na₃PO₄, so the limiting reactant is BaCl₂.
The number of moles of Ba₃(PO₄)₂ is:
Finally, the mass of Ba₃(PO₄)₂ is:
Therefore, should be obtained 1.02 grams of the precipitate.
I hope it helps you!
In the reaction given, 3.07 moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide.
<h3>STOICHIOMETRY:</h3>
According to this question, the following balanced equation is given:
2C6H14 + 19O2 → 12CO2 + 14H2O
Based on the above equation, 2 moles of hexane (C6H14) is burnt in oxygen to produce 12 moles of carbon dioxide (CO2).
This means that for 18.4 moles of carbon dioxide to be formed, (18.4 × 2)/12 = 3.07 moles of hexane must burn.
Therefore, 3.07 moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide.
Learn more about stoichiometry at: brainly.com/question/9743981
