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andrew-mc [135]
1 year ago
10

If you flipped two coins simultaneously, for a total of 24 times, how many times, on average, would you expect to get a head and

a tail?
Mathematics
1 answer:
Bingel [31]1 year ago
8 0

When two coins are flipped simultaneously 24 times, on average 12 times we will get a head and a tail.

For given question,

When two coins are tossed simultaneously, the sample space is as follows:

S = { HH, HT, TH, TT} where H denotes Head and T denotes tail.

Using the formula of probability,

P = Number of favorable outcomes/total number of outcomes,

we get,

P(HT) = 1/4

and

P(TH) = 1/4

We know that the occurrence of two mutually exclusive events is the sum of their individual probabilities.

So, P(Head on one and Tail on other)

= P(HT) + P(TH)

= 1/4 + 1/4

= 2/4

= 1/2

= 0.5

So, when two coins flipped simultaneously, the probability of flipping 2 coins and getting a head and a tail is 0.5

In this question, we need to find the number of times getting a head and a tail when two coins are flipped simultaneously 24 times

= 0.5 × 24

= 12

Therefore, When two coins are flipped simultaneously 24 times, on average 12 times we will get a head and a tail.

Learn more about the probability here:

brainly.com/question/3679442

#SPJ4

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Answer:

Let X be the event of feeling secure after saving $50,000,

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Since, the binomial distribution formula,

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Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

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(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

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(c) the probability of the number that say they would feel secure is at most five

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=0.95019264

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