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Sonja [21]
3 years ago
11

Hi everyone , Would you help me please :

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0
 
\displaystyle  \\ 
 \frac{1}{ \sqrt{2} } = \frac{1 \times \sqrt{2}}{ \sqrt{2} \times \sqrt{2}} = \boxed{\frac{\sqrt{2}}{2}}



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420!

840 x (3/7) = 360
840-360 = 480
480 x (1/8) = 60
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if alpha and beta are the roots of the equation 3x^2-9x+2=0 find the values of: (I) alpha ×beta + alpha^2 × beta. (ii) alpha^2-a
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Answer:

in steps

Step-by-step explanation:

The question did not state if alpha>beta or alpha<beta, so the answer will have 2 answers  for each questions

3x²-9x+2=0

x = (-(-9) ± √(-9)²-4*(3)*(2)) / (2*3)

x = (9 + √57) / 6   or x = (9 - √57) / 6      (alpha and beta) or (beta and alpha)

(I) alpha (a) ×beta (b) + alpha² × beta = ab (1+a)

   = ((9 + √57) / 6) ((9 - √57) / 6) (1 + (9 ± √57))  

   = ((9² - (√57)²)/36) (10 ± √57)

   = (24/36) (10 ± √57)

   = 2/3 (10 ± √57)   or (11.7 or 1.63)

(ii) alpha²-alpha×beta+beta² = a² -2ab + b² +ab = (a - b)² + ab

if a is alpha    

=​ ((9 + √57) / 6) - ((9 - √57) / 6)) + ((9 + √57) / 6) ((9 - √57) / 6))  

    = √57/3 + 2/3

     = (√57 + 2) / 3

if a is beta

((9 - √57) / 6) - ((9 + √57) / 6)) + ((9 - √57) / 6) ((9 + √57) / 6))  

    = - √57/3 + 2/3

     = - (√57 + 2) / 3

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

A. 37 isn't a number sentence

B. 49 + (-12) = 49-12. They're the same thing  because 49 minus 12 can also be written as 49 plus negative 12

C. 49 + 12 doesn't equal 49-12

D. 12- 49 = -37 which isn't equivalent to 49-12.

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