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Studentka2010 [4]
1 year ago
8

Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. this change is considered importa

nt because it:_________
Chemistry
1 answer:
Airida [17]1 year ago
6 0

Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. This change is considered important because it suggest that people may become addicted to behavior net just substance.

<h3>What is Gambling ? </h3>

Gambling disorder which involve repeated, problem gambling behavior. The behavior leads to problem for the individual families, and society.

The emotional and physical sign of gambling disorder are:

  • Anxiousness and Depression
  • Hopelessness
  • Lack of sleep
  • Pallor to skin
  • Gain loss of weight

<h3>What are the effects of gambling disorder ?</h3>

Gambling disorder make another kind of addiction that an individual uses to be able to deal with the situation. Start using the drugs alcohol to reduce the feeling of anxiety.

Thus from the above conclusion we can say that Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. This change is considered important because it suggest that people may become addicted to behavior net just substance.

Learn more about the Gambling Disorder here: brainly.com/question/28026101

#SPJ4

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In which state of matter would you expect to find water, at 20°C on Earth?
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Is a stick of dynamite potential energetic or kinetic
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Answer:Potential Energy

Explanation:

It is because a stick dynamite is a stored energy which have to be acted upon(lighting it) for it to explode

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Magnesium has three naturally occurring isotopes with masses of 23.99 amu, 24.99 amu, and 25.98 amu and natural abundances of 78
mihalych1998 [28]

Answer:24.31

Explanation:Contribution made by isotope of mass 23.99= 23.99×78.99=1894.97

Contribution made by isotope of mass 24.99=24.99×10.00=249.9

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Average mass=2430.91÷100

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3 0
3 years ago
Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N
Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of NaN_3

\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}

Molar mass of NaN_3 = 65.01 g/mole

\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 2 mole of NaN_3 react to give 3 mole of N_2

So, 0.311 moles of NaN_3 react to give \frac{0.311}{2}\times 3=0.466 moles of N_2

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = ?

n = number of moles N_2 = 0.466 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 22^oC=273+22=295K

Putting values in above equation, we get:

1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K

V=11.3L

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0
3 years ago
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