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Studentka2010 [4]
1 year ago
8

Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. this change is considered importa

nt because it:_________
Chemistry
1 answer:
Airida [17]1 year ago
6 0

Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. This change is considered important because it suggest that people may become addicted to behavior net just substance.

<h3>What is Gambling ? </h3>

Gambling disorder which involve repeated, problem gambling behavior. The behavior leads to problem for the individual families, and society.

The emotional and physical sign of gambling disorder are:

  • Anxiousness and Depression
  • Hopelessness
  • Lack of sleep
  • Pallor to skin
  • Gain loss of weight

<h3>What are the effects of gambling disorder ?</h3>

Gambling disorder make another kind of addiction that an individual uses to be able to deal with the situation. Start using the drugs alcohol to reduce the feeling of anxiety.

Thus from the above conclusion we can say that Dsm-5 includes gambling disorder as an addictive disorder, along with substance use disorders. This change is considered important because it suggest that people may become addicted to behavior net just substance.

Learn more about the Gambling Disorder here: brainly.com/question/28026101

#SPJ4

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The teacher tells your group to make a stock solution of sodium chloride, and then diluting it to
sergejj [24]

The idea here is that you need to figure out how many moles of magnesium chloride,

MgCl

2

, you need to have in the target solution, then use this value to determine what volume of the stock solution would contain this many moles.

As you know, molarity is defined as the number of moles of solute, which in your case is magnesium chloride, divided by liters of solution.

c

=

n

V

So, how many moles of magnesium chloride must be present in the target solution?

c

=

n

V

⇒

n

=

c

⋅

V

n

=

0.158 M

⋅

250.0

⋅

10

−

3

L

=

0.0395 moles MgCl

2

Now determine what volume of the target solution would contain this many moles of magnesium chloride

c

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n

V

⇒

V

=

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V

=

0.0395

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L

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Rounded to three sig figs and expressed in mililiters, the volume will be

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12.5 mL

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12.5-mL

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.

This is equivalent to diluting the

12.5-mL

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