Question

9.54 kJ of heat is required to raise the temperature of 225.0 g of a substance from 21.5 oC to 46 oC. Which of the following heat capacity corresponds to that substance?

Answer 1

Answer:

Specific heat capacity (c) = 1.7306J/g°C

Explanation:

Q = 9.54kJ = 9540J

Mass of the substance (m) = 225.0g

Initial temperature (T1) = 21.5°C

Final temperature (T2) = 46°C

Specific heat capacity of the substance (c)= ?

Heat energy (Q) = mc∇T

Q = heat energy in joules

M = mass in grams

c = specific heat capacity

∇T = change in temperature = T2 - T1

Q = mc∇T

Q = mc (T2 - T1)

9540 = 225 * c * (46 - 21.5)

9540 = 225c * 24.5

9540 = 5512.5c

c = 9540 / 5512.5

c = 1.7306J/g°C

Specific heat capacity of the substance is 1.7306J/g°C