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earnstyle [38]
3 years ago
14

9.54 kJ of heat is required to raise the temperature of 225.0 g of a substance from 21.5 oC to 46 oC. Which of the following hea

t capacity corresponds to that substance?
Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
8 0

Answer:

Specific heat capacity (c) = 1.7306J/g°C

Explanation:

Q = 9.54kJ = 9540J

Mass of the substance (m) = 225.0g

Initial temperature (T1) = 21.5°C

Final temperature (T2) = 46°C

Specific heat capacity of the substance (c)= ?

Heat energy (Q) = mc∇T

Q = heat energy in joules

M = mass in grams

c = specific heat capacity

∇T = change in temperature = T2 - T1

Q = mc∇T

Q = mc (T2 - T1)

9540 = 225 * c * (46 - 21.5)

9540 = 225c * 24.5

9540 = 5512.5c

c = 9540 / 5512.5

c = 1.7306J/g°C

Specific heat capacity of the substance is 1.7306J/g°C

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3 years ago
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How many grams of potassium chloride are needed to make 100 ml of a solution containing 250 mosmol/l? (m.w. of potassium is 39 a
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5 0
3 years ago
An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with
Katarina [22]

Answer:

Mass of the unknown acid is 4.0g

Explanation:

The determine the molar mass of the unknown acid, the steps below can be followed

Firstly, determine the concentration of the acid, the formula below can be used;

ConcA × Va/ConcB × Vb = Na/Nb

Where ConcA is the concentration of the unknown acid

ConcB is the concentration of the NaOH base

Va is the volume of acid and Vb is the volume of base

Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1

Thus

ConcA × 250/0.13 × 6.6 = 1/1

ConcA = 0.13 × 6.6/250

ConcA = 0.003432M

Then, determine the actual number of moles (n) of the unknown acid used,

ConcA = no of moles of acid/volume of acid (in dm³ or L)

To convert mL to L, we divide by 1000

Hence, 250ml = 0.25L

0.003432 = n/0.25

n = 0.003432 × 0.25

n = 0.01373 moles

To determine the molar mass;

n = mass/molar mass

The mass was given in the question to be 0.055g

Thus

0.01373 = 0.055/molar mass

molar mass = 0.055/0.01373

molar mass = 4.0g

5 0
3 years ago
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