molar concentration of AgNO₃ solution = 0.118 mole/L
Explanation:
Because we have the volume of the solution and there is no information about the density of the solution I will asume that you ask for the molar concentration.
number of moles = mass / molecular weight
number of moles of AgNO₃ = 10 / 170 = 0.0588
molar concentration = number of moles / volume (L)
molar concentration of AgNO₃ solution = 0.0588 / 0.5
molar concentration of AgNO₃ solution = 0.118 mole/L
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The empirical formula for the compound is - P₂O₅
the empirical formula is the simplest ratio of whole numbers of components in a compound.
molecular formula is the actual ratio of components in a compound.
we have to first find the number of empirical units in the molecular formula
molecular mass - 283.89 g/mol
mass of empirical formula - 283.8 g
number of empirical units - 283.89 g/mol / 283.8 g
number of empirical units - 1.000
therefore empirical formula = molecular formula
molecular formula - P₂O₅
Answer: The new concentration of a solution of
is 0.2 M 10.0 mL of a 2.0 M
solution is diluted to 100 mL.
Explanation:
Given:
= 10.0 mL,
= 2.0 M
= 100 mL,
= ?
Formula used to calculate the new concentration is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the new concentration of a solution of
is 0.2 M 10.0 mL of a 2.0 M
solution is diluted to 100 mL.
Shale actually forms in the part of the rock cycle called compaction.
<span>Transmutation
is the process of changing the substance, tangible or not, from one form to the
other. It means the transformation of one element in the periodic table into
another by one or a series of nuclear decays or reactions. One type of transmutation
is nuclear transmutation. Nuclear transmutation is the conversion of one
chemical element or isotope into another though nuclear reactions or nuclear
decay. Second type of transmutation is artificial transmutation. Artificial transmutation
occur in machinery that uses nough energy to cause changes in the nuclear
structure of the elements.</span>