Answer:
0.143 g of KCl.
Explanation:
Equation of the reaction:
AgNO3(aq) + KCl(aq) --> AgCl(s) + KNO3(aq)
Molar concentration = mass/volume
= 0.16 * 0.012
= 0.00192 mol AgNO3.
By stoichiometry, 1 mole of AgNO3 reacts with 1 mole of KCl to form a precipitate.
Number of moles of KCl = 0.00192 mol.
Molar mass of KCl = 39 + 35.5
= 74.5 g/mol
Mass = molar mass * number of moles
= 74.5 * 0.00192
= 0.143 g of KCl.
For the first one the pattern is multiply the previous number by five as you see 1 x 5 = 5 and so on. To keep adding to it you would do
125 x 5 = 625 625 x 5 = 3125 3125 x 5 = 15625
Now for the second one the pattern is divide the previous number by three as you can see 2187 / 3 = 729 and so on. To keep going you would
81 / 3 = 27 27 / 3 = 9 9 / 3 = 3
I hope this helps you and if you have anymore questions i'll be glad to answer them.
Solution:- Hypochlorite ion
has one Cl and one O atom. Cl has 7 valence electrons and O has 6 valence electrons. Since there is one negative charge on the ion,
total valence electrons = 7 + 6 +1 = 14
(note:- if there is negative charge then it is added and if there is positive charge then it is subtracted while calculating the valence electrons)
Both Cl and O atoms wants to complete their octet and so for this we put a single bond between them. Single bond means two electrons, so the remaining electrons would be 14 - 2 = 12
It means 12 electrons will be placed as lone pair of electrons. To complete the octet, we put 6 dots around each of the atom. Oxygen is more electron negative than Cl, so we show the -1 charge for oxygen.
I think it is C because photosynthesis converts solar energy
Answer:
a) 213.3 mg/L
b) 62.61 mg/L
c) 0.0225 mg/L
Explanation:
Theoretical oxygen demand (ThOD)is essentially the amount of oxygen required for the complete degradation of a given compound into the final oxidized products
a) Given:
Concentration of acetic acid,
= 200 mg/L


Based on the reaction stoichiometry:
mass of
= 60 g
mass of
= 2(32) = 64 g

b) Given:
Concentration of ethanol,
= 30 mg/L


Based on the reaction stoichiometry:
mass of
= 46 g
mass of
= 3(32) = 96 g

c) Given:
Concentration of sucrose,
= 50 mg/L


Based on the reaction stoichiometry:
mass of
= 342 g
mass of
= 12(32) = 384 g
