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2 years ago

What are the ordered pairs of the

Mathematics

1 answer:

Sholpan [36]2 years ago

5 0

Answer:

its definitvely 6

Step-by-step explanation:

2 by 4 by the 3 empfs and by the 123 divided by the 360 and by the iscoceles and the 4 cohedrons

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Determine which postulate or theorem can be used to prove that

EleoNora [17]

Answer:

$\triangle ABC \cong \triangle DCB$ by AAS

Step-by-step explanation:

According to the following two triangles, $\triangle ABC$ and $\triangle DCB$ are congruent by Angle-Angle-Side (AAS), because there are two angles shown and share a side, which is in the middle between triangles.

7 0

2 years ago

Consider the function f (x) = x2.

klio [65]

Answer: The graph is shifted 2 units to the right.

Step-by-step explanation:

Given a function f(x), we know that one transformation rule is:

If $f(x-k)$ then the function is shifted "k" units to the right.

Therefore, for the function $f(x)=x^{2}$ , when we subtract 2 from the input, then we get the function g(x) in the form:

$g(x)=(x-2)^{2}$

We can conclude that subtracting 2 from the input of the function $f(x)=x^{2}$ , then the graph is shifted 2 units to the right.

5 0

2 years ago

Read 2 more answers

In the fallowing diagram, it is shown that mEHG is a right angle, mEHF = x+ 1 and mGHF = 5x+5. Find the value of x, the numerica

GalinKa [24]

Answer:

x = 14

EHF = 15 degree GHF = 75 degree

Step-by-step explanation:

(x+1) + (5x+5) = 90

(x+5x)+ (1+5) = 90

6x + 6 = 90

6x = 90-6

6x = 84

x = 84/6

x = 14

EHF + GHF = 90 degree

EHF = x+1

= 14 + 1 = 15

= 15 degree

GHF = 5x+5

= 14 x 5 (+5) = 70 + 5

= 75 degree

EHF = 15 degree GHF = 75 degree

4 0

2 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

4 0

3 years ago

Factorise each of the following.

Alborosie

I will do (a) only.

6rt - 3st + 6ru - 3su

6rt - 3st = 3t(2r - s)

6ru - 3su = 3u(2r - s)

Answer: (3t + 3u)(2r - s)

Do the rest likewise.

7 0

2 years ago