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Anettt [7]
10 months ago
11

Which pair of equations generates graphs with the same vertex?

Mathematics
2 answers:
puteri [66]10 months ago
6 0

Answer:

The pair of equations that generates graphs

with the same vertex is :

y = –4x²   ;    y = 4x²

Step-by-step explanation:

<u><em>A quadratic function can be written in the form  f(x) = a(x – h)² + k, where a, h, and k are constants. </em></u>

<u><em>It’s graph is a parabola which has a vertex at (h, k).</em></u>

• The graph of the equation y = – (x + 4)² = – [x – (–4)]² + 0

has a vertex at (-4 , 0).

On the other hand ,The graph of the equation y = (x – 4)² = (x – 4)² + 0

has a vertex at (4 , 0).

Therefore , the two equations generate graphs with <u>different</u> vertices.

• The graph of the equation y = –4x² = –4 (x –0)² + 0

has a vertex at (0 , 0).

On the other hand ,The graph of the equation y = 4x² = 4 (x –0)² + 0

has a vertex at (0 , 0).

Therefore , the two equations generate graphs with <u>the same</u> vertex.

• The graph of the equation y = – x² – 4 = – (x – 0)² + (– 4)

has a vertex at (0 , -4).

On the other hand ,The graph of the equation y = x² + 4 = (x – 0)² + 4

has a vertex at (0 , 4).

Therefore , the two equations generate graphs with <u>different</u> vertices.

• The graph of the equation y = (x – 4)² = (x – 4)² + 0

has a vertex at (4 , 0).

On the other hand ,The graph of the equation y = x² + 4 = (x – 0)² + 4

has a vertex at (0 , 4).

Therefore , the two equations generate graphs with <u>different</u> vertices.

zvonat [6]10 months ago
5 0

Answer:

D

Step-by-step explanation:

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Answer:

y = 5x+3

Step-by-step explanation:

a general line is represented by the equation:

y = mx + n

a line with m=5, that goes through (-1,-2), should satisfy the equation:

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4 0
1 year ago
What is equivalent to 32/40
WARRIOR [948]
4/5 is a fraction equivalent to 32/40.  This is in simplest form.
Another fraction that is equivalent to 32/40 is 16/20.
3 0
3 years ago
Read 2 more answers
Below are the jersey numbers of 11 players randomly selected from a football team. Find the​ range, variance, and standard devia
padilas [110]

Answer:

Option(A) is correct

Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

Step-by-step explanation:

The given data set in the question are ;33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58

the range can be determined by finding the highest value and subtract it to the lowest value. In this case the values are:

Highest = 97

Lowest = 71

Range = highest value - Minimum value

Range = 97 - 26 = 71

Range= 71

mean of the data is the summation of all the numbers in the data set divided by the number of given samples.

Mean = (33 + 29 + 97 + 56+ 26 + 78 + 83 74+ 65 + 47 + 58)/11

= 647/11

Mean value =58.7

Now to find the variance of the data set by using below formular

σ²=[ (xᵢ -mean)²]/n-1

[(33-58.7)² +(29-58.7)²+( 97-58.7)²+( 56-58.7)²+( 26 -58.7)²+(78-58.7)²+( 83 -58.7)²+(74-58.7)²+( 65-58.7)²+( 47 -58.7)²+(58 -58.7)²]/10

Variance=546

Now, we will calculate standard deviation by taking square root over variance

σ =√(variance)

σ =√(546)

Standard deviation= 23.4

Hence, the range is 71 ,variance is 546 and standard deviation is 23.4 therefore,

Option A is the answer that is Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

5 0
2 years ago
Use the identity (x+y)(x−y)=x2−y2 to find the difference of two numbers if the sum of the numbers is 12 and the difference of th
Natalka [10]

Answer:

The difference of two numbers using identity (x+y)(x-y)=x^2-y^2 is 4.

Step-by-step explanation:

Given:  The sum of the numbers is 12 and the difference of the squares of the numbers is 48.

To find the difference of two numbers using identity (x+y)(x-y)=x^2-y^2

Let the two numbers be a and b, then

Given that the sum of the numbers is 12

that is a + b = 12 .........(1)

Also, given the difference of the squares of the numbers is 48.

that is a^2-b^2=48     ..........(2)

Using given identity  (x+y)(x-y)=x^2-y^2

We have (a+b)(a-b)=a^2-b^2

Substitute the known values, we have,

12(a-b)=48

Divide both side 12 , we have,

(a-b)=4

Thus, the difference of two numbers using identity (x+y)(x-y)=x^2-y^2 is 4.

8 0
3 years ago
Read 2 more answers
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