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2 years ago

Use exponents to write an expression for one billion

Mathematics

1 answer:

kykrilka [37]2 years ago

5 0

The anser would be 500 with the exponet of 100 solve my multiplying

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Gabe Amodeo, a nuclear physicist, needs 60 liters of a 60% acid solution. He currently has a 50% solution and a 70% solution.

FromTheMoon [43]

Answer:

Gabe needs 20 liters of the 40% solution.

He also needs 40 liters of the 70% solution.

Step-by-step explanation:

Equation:

acid + acid = acid

0.40x + 0.70(60-x) = 0.60*60

40x + 70*60 - 70x = 60*60

-30x = -10*60

x = 20 liters

Gabe needs 20 liters of the 40% solution.

He also needs 40 liters of the 70% solution.

6 0

3 years ago

Help me pls the questions are here

andreyandreev [35.5K]

3x + 7 = -x - 1
3x + 7 + = -1
4x + 7 = -1
4x = -1 - 7
4x = -8
x = -2

1 - 2x + 5 = 4x - 3
-2x + 6 = 4x - 3
6 = 4x - 3 + 2x
6 = 6x - 3
6 + 3 = 6x
9 = 6x
x = 6/9
x = 2/3

i helped you with the first two questions so you can see how you can solve it.

hope this helps, God bless!

6 0

2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

yarga [219]

Answer:

$(x-5)^2+(y-2)^2=9\\$

Step-by-step explanation:

So, you basically want the equation of the circle.

Given:

Center(C): $C(5, 2)$

$r=3$

The equation of circle is:

$(x-h)^2+(y-k)^2=r^2\\$

Where, $(h, k)$ represents the center point and $r$ is the radius of the circle.

Plotting the values in the equation:

$(x-5)^2+(y-2)^2=3^2\\$

$(x-5)^2+(y-2)^2=9\\$

This is the equation of the circle of center (5, 2) and radius 3.

6 0

3 years ago

TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

stich3 [128]

Answer:

A. It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

It would be needed 20 packets to transmit 30,000 bytes of information

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Note: Same answer provided to question 14037480, answered by me.

7 0

2 years ago

What are composite for 48?

weqwewe [10]

It can be divided by 8 and 6. 8x6=48.

3 0

3 years ago