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Stolb23 [73]
3 years ago
6

Use exponents to write an expression for one billion

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0
The anser would be 500 with the exponet of 100 solve my multiplying
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A help would be greatly appreciated! 
dalvyx [7]
The tree was approximately 40.8ft tall.

You use the equation, a^2+b^2=c^2.
12^2 + 39^2 = x^2, add the results of 12^2 and 39^2 to make 1665 = x^2. You can take the positive root of both sides, 3√185, and it equals 40.80441152, which is rounded to 40.8.
7 0
3 years ago
What is the sum 2, 3, 4, and 5?
borishaifa [10]

Answer:

14

Step-by-step explanation:

We can find the sum of these numbers by adding them together.

The cumulative rule of addition lets us add numbers together in any order we want.

So, for 2 + 3 + 4 + 5 …

2 + 3 = 5

So now we have 5 + 4 + 5

5 + 4 = 9

Now we have 9 + 5

And 9 + 5 = 14

So, your answer is 14

Hope this helps!

4 0
2 years ago
What is 0.03% written as a decimal?<br> O A. 0.3<br> O B. 0.0003<br> O C. 0.003<br> O D. 0.03
ch4aika [34]







It is 0.03 just take out the percent
4 0
3 years ago
Read 2 more answers
Suppose Joe earned three times as much as Marty during the summer.Together they earned 210.How much did each earn?
JulijaS [17]

Answer:

Marty got 70 and then Joe earned 3 times it

Step-by-step explanation:


7 0
3 years ago
Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result
Vaselesa [24]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

5 0
2 years ago
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