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Sunny_sXe [5.5K]
1 year ago
10

E4.2 Simplify the following using suitable properties (a) 109x 50​

Mathematics
2 answers:
oksian1 [2.3K]1 year ago
8 0

Answer:

5450

Step-by-step explanation:

You can just use a caculater to get the answer.

lys-0071 [83]1 year ago
5 0

109×50

100×50+9×50=5000+450

5450

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B<br> 45°<br> 71°<br> E<br> 27°<br> A<br> D<br> 11. What is mBAC
ANEK [815]

Answer:THE ANSWER IS B MY GUY

Step-by-step explanation:

3 0
2 years ago
The first triangle is an enlargement of the second.
insens350 [35]

Answer:

large triangle:

base = 6.64 cm

hypotenuse = 8.31 cm

small triangle:

base = 4 cm

Step-by-step explanation:

large triangle:

tan 37 = 5/base

0.7536 = 5/base

base = 6.64 cm

using the Pythagorean theorem:

hypotenuse² = 5² + 6.64²

hypotenuse² = 25 = 44.02 = 69.02

hypotenuse = 8.31 cm

small triangle:

using the Pythagorean theorem:

base² = 5² - 3²

base² = 25 - 9 = 16

base = 4 cm

3 0
3 years ago
How do I determine which is y=-1/3x+2?
Jlenok [28]

Step-by-step explanation:

This is a linear equation in slope intercept form which is

y = mx + b

where m is the slope and b is the y intercept.

The equation

y =  -  \frac{1}{3} x + 2

Has a slope of -1/3 so this means that the slope will be decreasing. A negative linear equation increases as we go left. and decreases as we go right. The y intercept is 2. So this means the graph must pass through (0,2) and when x=0, y must be 2.

In other words, look for a line that the y values increase as we go left and decrease we go right. Also look for a point (0,2) and make sure the graph pass through it.

6 0
3 years ago
Calculus 3 chapter 16​
o-na [289]

Evaluate \vec F at \vec r :

\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k

Compute the line element d\vec r :

d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt

Simplifying the integrand, we have

\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt

Then the line integral evaluates to

\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}

3 0
1 year ago
Sylvie finds the solution to the system of equations by graphing. y = x + 1 and y = x – 1 Which graph shows the solution to Sylv
Furkat [3]
Graphs of y = x+- 1 and of y = x - 1 are shown in the figure below.
The intersection of the two graphs is the solution for the two equations.

Answer:
There is no solution.

Explanation:
It is clear that the two lines are parallel and will never intersect.

Note that the equation for a straight line is of the form
y = mx + b
where
m = slope,
b = y-intercept.

y = x + 1 has slope of m=1.
y = x - 1 has slope of m=1.
The two slopes are equal.
Because parallel lines do not intercept, there is no solution.

6 0
3 years ago
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