Complex solutions, namely roots with a √(-1) or "i" in it, never come all by their lonesome, because an EVEN root like the square root, can have two roots that will yield the same radicand.
a good example for that will be √(4), well, (2)(2) is 4, so 2 is a root, but (-2)(-2) is also 4, therefore -2 is also a root, so you'd always get a pair of valid roots from an even root, like 2 or 4 or 6 and so on.
therefore, complex solutions or roots are never by their lonesome, their sister the conjugate is always with them, so if there's a root a + bi, her sister a - bi is also coming along too.
if complex solutions come in pairs, well, clearly a cubic equation can't yield 3 only.
The slope-intercept form of a line:
We have:
Substitute:
Put the values of coordinates of the point (1, 5) to the equation of a line:
Answer: 
Answer:
see explanation
Step-by-step explanation:
Using the cofunction identities
tan(90 - A) = cotA and cscA = sec(90- A)
Consider the left side
tanA + tan(90 - A)
= tanA + cotA
= 
+ 
= 
= 
= 
× 
= secA × cscA
= secA. sec(90 - A) = right side ⇒ verified
Answer:
20
Step-by-step explanation:
2x + 10 = 50
-10 -10
2x = 40
x = 20
