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In-s [12.5K]
3 years ago
5

Help me please. Very much appreciated​

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
4 0

Answer:

A = 23.2 mm²

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Here b = 8 and h = 5.8 , then

A = 0.5 × 8 × 5.8 = 4 × 5.8 = 23.2 mm²

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Step-by-step explanation:

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That is called the multiplicative identity property.
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A hospital recorded the weights, in ounces, of newborn babies for two weeks. The
Gwar [14]

Answer:

The standard deviation for week two was about 3 ounces more than the standard deviation for week one

Step-by-step explanation:

Given

Week\ 1: 128, 105, 80, 82, 96, 98, 87, 100, 112, 126

Week\ 2: 75, 85, 90, 97, 89, 105, 110, 127, 129, 130

<em>See attachment for options</em>

Required

The true statement

<u>Checking the standard deviation</u>

<u>For week 1</u>

Calculate the mean:

\bar x = \frac{\sum x}{n}

\bar x = \frac{128+ 105+ 80+ 82+ 96+ 98+ 87+ 100+ 112+ 126}{10}

\bar x = \frac{1014}{10}

\bar x_1 = 101.4

Then standard deviation

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}

\sigma_1 = \sqrt{\frac{(128 - 101.4)^2 +............+ (126- 101.4)^2}{10}}

\sigma_1 = \sqrt{\frac{2522.4}{10}}

\sigma_1 = \sqrt{252.24

\sigma_1 = 15.88

For week 2, we have:

\bar x = \frac{75+ 85+ 90+ 97+ 89+ 105+ 110+ 127+ 129+ 130}{10}

\bar x = \frac{1037}{10}

\bar x_2 = 103.7

Then standard deviation

\sigma_2 = \sqrt{\frac{(75 - 103.7)^2 +................+ (130- 103.7)^2}{10}}

\sigma_2 = \sqrt{\frac{3538.1}{10}}

\sigma_2 = \sqrt{353.81

\sigma_2 = 18.81

Compare the standard deviations

\sigma_1 = 15.88

\sigma_2 = 18.81

Calculate the difference:

d = \sigma_2 - \sigma_1

d = 18.81 - 15.88

d = 2.93

d \approx 3

<em>This implies that option (b) is true</em>

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3 years ago
Which point is a solution to the system?
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Answer:

C. (2;9)

Step-by-step explanation:

for more details see the attachment.

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