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kirza4 [7]
1 year ago
15

√(2x+1) Evaluate the integral 2 (2x + 1) In (2x + 1) dx.

Mathematics
1 answer:
Crank1 year ago
6 0

Substitute y=\ln(2x+1) and dy=\frac2{2x+1}\,dx, so that

\displaystyle \int \frac2{(2x+1) \ln(2x+1)} \, dx = \int \frac{dy}y = \ln|y| + C = \boxed{\ln|\ln(2x+1)| + C}

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  4. Multiplication
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Distributive Property

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 5x + 7

g(x) = 3x - 1

<u>Step 2: Find</u>

  1. Substitute in functions:                                                                                    f(g(x)) = 5(3x - 1) + 7
  2. [Distributive Property] Distribute 5:                                                                 f(g(x)) = 15x - 5 + 7
  3. [Addition] Combine like terms:                                                                        f(g(x)) = 15x + 2
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