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kirza4 [7]
1 year ago
15

√(2x+1) Evaluate the integral 2 (2x + 1) In (2x + 1) dx.

Mathematics
1 answer:
Crank1 year ago
6 0

Substitute y=\ln(2x+1) and dy=\frac2{2x+1}\,dx, so that

\displaystyle \int \frac2{(2x+1) \ln(2x+1)} \, dx = \int \frac{dy}y = \ln|y| + C = \boxed{\ln|\ln(2x+1)| + C}

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What is the area of the triangle?<br> 9 4 12
LUCKY_DIMON [66]

Answer:

  13.636

Step-by-step explanation:

The area can be found using Heron's formula:

  A = √(s(s-a)(s-b)(s-c))

where s=(a+b+c)/2.

For the given triangle, ...

  a=9, b=4, c=12, s=(9+4+12)/2 = 12.5

  A = √(12.5(3.5)(8.5)(0.5)) = √185.9375 ≈ 13.636

The area of the triangle is about 13.636 square units.

7 0
3 years ago
The tubs are similar in shape.
faltersainse [42]

Answer:

The tube are similar in shape.

The height of the small tub is 5  cm.

The volume of the small tube is 150  cm3.

The volume of the large tub is 500  cm3.

Work out the height of the large tub.

Give your answer correct to 3  significant figures.

Step-by-step explanation: Hope this help(:

3 0
1 year ago
Read 2 more answers
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
4. If Mahamat has 36 coins totaling $3.00, and the coins are all nickels and quarters, how many of each coin does he have?​
MakcuM [25]

The answer is 30 i believe :) ♡

6 0
3 years ago
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borishaifa [10]
Use the bmxy chart b should be your other ¨y¨ so do 5= 2/3(2)+b and whatever u get for ¨b¨ should be your answer 

8 0
4 years ago
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