Answer:
3
Step-by-step explanation:
Pythagorean Theorem: a²+b²=c²
You can fill in the numbers you know: a²+4²=5²
(Hypotenuse must be side c)
Square those numbers and you have: a²+16=25
Subtract 16 from both sides: a²=9
Square root both sides and you get: a=3
Answer:
-3
Step-by-step explanation:
There's a three point distance between the two on a coordinate plane
Answer:
![x = y^3+5y](https://tex.z-dn.net/?f=x%20%20%3D%20y%5E3%2B5y)
Step-by-step explanation:
Complete question
![\frac{x - 5y}{y^3} - 1=0\\](https://tex.z-dn.net/?f=%5Cfrac%7Bx%20-%205y%7D%7By%5E3%7D%20-%201%3D0%5C%5C)
Required
Solve for x
We have:
![\frac{x - 5y}{y^3} - 1=0](https://tex.z-dn.net/?f=%5Cfrac%7Bx%20-%205y%7D%7By%5E3%7D%20-%201%3D0)
Collect like terms
![\frac{x - 5y}{y^3} = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%20-%205y%7D%7By%5E3%7D%20%3D%201)
Multiply through by ![y^3](https://tex.z-dn.net/?f=y%5E3)
![x - 5y = y^3](https://tex.z-dn.net/?f=x%20-%205y%20%3D%20y%5E3)
Make x the subject
![x = y^3+5y](https://tex.z-dn.net/?f=x%20%20%3D%20y%5E3%2B5y)
Answer:
Common difference is 4
Step-by-step explanation:
25 , 29, 33,37,41
Answer:
135 degrees
![S45^{0}E](https://tex.z-dn.net/?f=S45%5E%7B0%7DE)
Step-by-step explanation
Consider the attached diagram
we are required to find the bearing of the aeroplane,
Consider the right angled triangle BOE
|OB|=4 unit
|AB|=4 Units
![Tan \alpha =\frac{Opposite}{Adjacent} =\frac{4}{4} \\\\\alpha=Tan^{-1} 1=45 degrees](https://tex.z-dn.net/?f=Tan%20%5Calpha%20%3D%5Cfrac%7BOpposite%7D%7BAdjacent%7D%20%3D%5Cfrac%7B4%7D%7B4%7D%20%5C%5C%5C%5C%5Calpha%3DTan%5E%7B-1%7D%201%3D45%20degrees)
The Bearing of the Aeroplane is therefore given:
(i)From North Clockwise as: 90+45 =135 degrees
(ii)From a North South Line as