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marshall27 [118]
1 year ago
13

Find the fourth roots of i

Mathematics
1 answer:
antoniya [11.8K]1 year ago
4 0

Answer:

  1∠22.5°, 1∠112.5°, 1∠202.5°, 1∠292.5°

Step-by-step explanation:

A root of a complex number can be found using Euler's identity.

<h3>Application</h3>

For some z = a·e^(ix), the n-th root is ...

  z = (a^(1/n))·e^(i(x/n))

Here, we have z = i, so a = 1 and z = π/2 +2kπ.

Using r∠θ notation, this is ...

  i = 1∠(90° +k·360°)

and

  i^(1/4) = (1^(1/4))∠((90° +k·360°)/4)

  i^(1/4) = 1∠(22.5° +k·90°)

For k = 0 to 3, we have ...

 for k = 0, first root = 1∠22.5°

  for k = 1, second root = 1∠112.5°

  for k = 2, third root = 1∠202.5°

  for k = 3, fourth root = 1∠292.5°

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Answer:

See explanations below

Step-by-step explanation:

Given the system of equation

2x - 10 y = -30 ... 1

x - 5y = 20 ... 2

Step: From 2;

x = 20 + 5y ...3

Step 2: Substitute equation 3 into 1

2x - 10y = -30

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Open the bracket

10y + 40 - 10y = -30

10y - 10y + 40 = -30

0+40 = -30

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The steps taken by Teri are correct all through. He didn't make any error whatsoever

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Step-by-step explanation:

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Answer:

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Ok that's not it

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Step-by-step explanation:

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Step-by-step explanation:

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