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Murljashka [212]
9 months ago
6

Work out in a standard form. A) 2.1x 10^-5 ÷7 x 10^-2​

Mathematics
2 answers:
Dima020 [189]9 months ago
7 0

Answer: 3*10⁻⁴.

Step-by-step explanation:

\displaystyle\\2,1*10^{-5}\div7*10^{-2}=\\\frac{2,1*10^{-5}}{7*10^{-2}}=\\ \frac{2,1}{7}*10^{-5-(-2)}=\\ 0,3*10^{-5+2}=\\0,3*10^{-3}=\\3*10^{-4}.

EleoNora [17]9 months ago
5 0

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

<h3>Given:</h3>

▪ \longrightarrow \sf{\dfrac{2.1 \times  {10}^{5} }{7 \times  {10}^{ - 2} } }

First, rewrite the numerator in such a way that the coefficient 2.1 becomes 21:

\small\longrightarrow \sf{\dfrac{21 \times  {10}^{ - 6} }{7 \times  {10}^{2} } }

Divide the coefficient:

\small\longrightarrow \sf{21 \div 7=3}

Divide the base by subtracting the exponents of the base 10.

\small\longrightarrow \sf{-6(-2) \Longrightarrow -6+2=-4}

\leadsto Hence, the quotient of the given expression has a coefficient of 3 and the exponent of the base 10 is -4.

\small\longrightarrow \sf{3 \times 10^{-4}}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\large \bm{The \:  \: quotient \:  \: is  \: \: 3 \times  {10}^{ - 4} .}

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Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
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Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

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