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Natalija [7]
2 years ago
11

A rhombus is a four-sided figure with all sides the same length.

Mathematics
1 answer:
kumpel [21]2 years ago
4 0

The perimeter of the rhombus FGHJ is 20 units

<h3>How to graph the rhombus</h3>

The coordinates are given as:

F = (-2, -2)

G = (-2, 3)

H = (2, 6)

From the question, we understand that vertex J is directly below vertex H.

This means that vertices H and J have the same x coordinate.

So, we have

J = (2, y)

The distance between F and G is 5 units,

So, we have

J = (2, y - 5)

Where

y = 6 i.e. the y coordinate of H

This gives

J = (2, 6 - 5)

Evaluate

J = (2, 1)

See attachment for the graph of the rhombus

<h3>The perimeter</h3>

In (a), we have:

The distance between F and G is 5 units,

This means that

FG = 5

The side lengths of a rhombus are equal.

So, the perimeter is

P = 4 * FG

This gives

P =4 * 5

Evaluate

P = 20

Hence, the perimeter of the rhombus is 20 units

Read more about rhombus at:

brainly.com/question/26154016

#SPJ1

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Which graph best represents the download speed of a large file
stellarik [79]

Answer:

This question is incomplete

Step-by-step explanation:

This question is incomplete. However, there are mainly four types of graphical representations in mathematics; line graph, bar graph (and histogram), pie chart and cartesian graph. The most suitable representation for fluctuating data sets of the same variables on each of the y and x-axis is the line graph. Since download speed will fluctuate during the course of a download, the correct type of graph to be used here will be the line graph. And the exact type of line graph that will be used here is a simple line graph. A simple line graph is a type of line graph in which one line is drawn on the graph. A simple line graph is usually used to represent two variables (in this case data downloaded per time).

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Is it bad that my step dad is calling me bad names?
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Read 2 more answers
At a​ museum, adult admission is $ 13.00 and children admission is $ 7.50. During one​ day, a total of 1900 adult and children a
bagirrra123 [75]

Answer:

1400 adult admissions.

Step-by-step explanation:

At a museum, adult admission is $13.00

Children admission is $7.50

During one day, a total of 1900 adult and children admissions were collected

And $21,950 in admission fees was collected.

Let adult admissions during that day be x,

And children admissions be y

The simultaneous equation formed is;

x + y = 1900 ... (i)

$13x + $7.50y = $21,950 ... (ii)

Multiplying (i) by 13 and (ii) by 1 we get;

13x + 13y = 24,700  ... (i)

13x + 7.50y = 21,950 ... (ii)

(i) - (ii) we get;

5.5y = 2750

y = 500

So there were 500 children admissions and 1900 - 500 = 1400 adult admissions.

8 0
3 years ago
How would I solve this?
m_a_m_a [10]

Answer:

3(6)-1

----------------

2(6)+1

Step-by-step explanation:

r(x) = 3x-1

s(x) = 2x+1

r(6) / s(6)

r(6) = 3(6)-1

s(6) = 2(6)+1

Putting r(6)/ s(6)

3(6)-1

----------------

2(6)+1

8 0
3 years ago
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