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creativ13 [48]
3 years ago
6

Which equations could be used to solve for the unknown lengths of ABC? Check all that apply.

Mathematics
1 answer:
Alborosie3 years ago
6 0

It's A and E.


Thank me later-



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A rectangle has an area of 32 square feet and a perimeter of 24 feet
Georgia [21]

Answer:

length = 8 feet

width = 4 feet

Step-by-step explanation:

l x w = 32

2l + 2w = 24

l = 8

w = 4

3 0
3 years ago
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
Oduvanchick [21]
Remember that (g-f)(x) is g(x)-f(x). We know form our problem that f(x)=4-x^2 and g(x)=6x, so:
(g-f)(x)=g(x)-f(x)
(g-f)(x)=6x-(4-x^2)
(g-f)(x)=6x-4+x^2

Now, to find (g-f)(3), we just need to evaluate (g-f)(x) at 3. In other words, we are going to replace x with 3:
(g-f)(x)=6x-4+x^2
(g-f)(x)=6(3)-4+(3)^2

We can conclude that the correct answer is <span>C.6(3) – 4 + 3^2 </span>

5 0
3 years ago
What is the slope of the line through (–5,2) and (6,7) in the standard (x,y) coordinate plane?
sergiy2304 [10]

Step-by-step explanation:

slope =   \frac{\triangle \: y}{\triangle \: x}  \\  =  \frac{(7 - 2)}{(6 - ( - 5))}  \\  =  \frac{5}{11}  \\ slope = (5 ,11)

5 0
3 years ago
Can someone help me with this question
horsena [70]

Step-by-step explanation:

Given: diameter = 16 in

hence radius, r is 16 ÷ 2 = 8 in

a) notice that the fan blades divide the circle into 3 equal sectors.

Each sector is hence 1/3 of the entire circumference of the circle

Arc Length of each sector (between blades),

=  (1/3) x circumference

= (1/3) x 2πr

= (1/3) x 2 x 3.142 x 8

= 16.76 in (Answer)

b) similarly, the area between the blades

= (1/3) x πr²

= (1/3) x 3.142 x 8²

= 67.03 in² (answer)

c) The angular velocity is the radians per second that the tip moves

It is given that it moves 8π radians in 2 seconds

hence in 1 second, we expect the tip to move,

8π ÷ 2 = 4π rad/s (Answer)

6 0
4 years ago
A student survey asked: "How tall are you (in inches)?" Here's the data:
lidiya [134]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
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