A projector enlarges an image in the ratio 20:1. What will be the size of an enlargement of a picture that is 8cm by 6cm?
1 answer:
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Answer:
![a=2[d-V_0t]/t^2=2d/t^2-2v_0/t](https://tex.z-dn.net/?f=a%3D2%5Bd-V_0t%5D%2Ft%5E2%3D2d%2Ft%5E2-2v_0%2Ft)
Explanation:
Since, you have not included the formula, I will work here with the formula for constant accelaration motion that relates the four variables: displacement (d), Vo (initial velocity), a (acceleration) and t (time).
1) displacement formula:
2) Subtract the term Vot from both sides:
3) Multiply both sides by 2:
4) Divide both sides by t²
![2[d-V_0t]/t^2=a](https://tex.z-dn.net/?f=2%5Bd-V_0t%5D%2Ft%5E2%3Da)
So, you have obtainded:
a = 2[d - Vo×t] / t²
Yet, you can arrange it in different ways. For example, you might separate into two terms:
Explanation:
Since, you have not included the formula, I will work here with the formula for constant accelaration motion that relates the four variables: displacement (d), Vo (initial velocity), a (acceleration) and t (time).
1) displacement formula:
2) Subtract the term Vot from both sides:
3) Multiply both sides by 2:
4) Divide both sides by t²
So, you have obtainded:
a = 2[d - Vo×t] / t²
Yet, you can arrange it in different ways. For example, you might separate into two terms: